Ranking of an array.

2011 10 9
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Hi, How can I do array rank of a matrix. Such that: [1,5; 7 9; 2 0] will produce [2 4; 5 6; 1 3]. I mean, all variables should be /ranked in an increment order. Lowest will be 1, the highest will be n

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bym
bym 2011-10-9
how does [1,5; 7 9; 2 0] produce [2 4; 5 6; 1 3]?
I don't understand what your goal is

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Jan
Jan 2011-10-9

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I assume, the result should be [2 4; 5 6; 3 1] with the last two elements swapped. The method is called sorting, not ranking.
M = [1,5; 7 9; 2 0];
[dummy, index] = sort(M(:));
R(index) = 1:numel(M);
R = reshape(R, size(M));

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Abdullah Muratoglu
Abdullah Muratoglu 2011-10-9
Absolutely correct.
Thanks
Abdullah Muratoglu
Abdullah Muratoglu 2011-10-10
I realized, this code gives the same numbers, different ranks/sorts.
E.g: [3 3] will be ranked as [1 2] not [1 1]. How can I overcome this?
Andrei Bobrov
Andrei Bobrov 2011-10-10
A = [6 7
7 3
4 1]
[a, ignore, c] = unique(A);
B = A;
a1 = 1:numel(a);
B(:) = a1(c)
Abdullah Muratoglu
Abdullah Muratoglu 2011-10-10
perfect!
Thanks

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