compare two string and pass the selected data within it

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Santosh Biradar
Santosh Biradar 2022-8-30
回答： Santosh Biradar 2022-8-30
Hello
There are two strings.
chkDataFileName = ["20220329_112048_ADU_INPUT" ; "20220329_141153_ADU_INPUT" ; "20220329_142653_ADU_INPUT" ; "20220329_144153_ADU_INPUT" ; 20220329_160005_ADU_INPUT"]
Newlyaddednames = ["20220329_112048_1742.4" ; "20220329_112048_1760.2" ; "20220329_141153_3216.8" ; "20220329_142653_3802.2" ; "20220329_144153_4720.2" ; "20220329_160005_1738"]
for eg., compare both string, as 20220329_112048 is present in both string then it will result as,
>>BLF_Name="20220329_112048_ADU_INPUT"; SnapTime = "1742.4"
>>BLF_Name="20220329_112048_ADU_INPUT"; SnapTime = "1760.2"
Now compare both string, as 20220329_141153 is present in both string then it will send the result as,
>>BLF_Name="20220329_141153_ADU_INPUT"; SnapTime = "3216.8"
same result for rest
>>BLF_Name="20220329_142653_ADU_INPUT""; SnapTime = "3802.2"
>>BLF_Name="20220329_144153_ADU_INPUT""; SnapTime = "4720.2""
>>BLF_Name="20220329_160005_ADU_INPUT""; SnapTime = "1738"
Please let me know for brief.
Thank you
  2 个评论
Image Analyst
Image Analyst 2022-8-30
Will it always be the first 15 characters you're looking at when you try to match up strings? Or maybe up until you see "_ADU"?
Santosh Biradar
Santosh Biradar 2022-8-30
编辑：Santosh Biradar 2022-8-30
Yes it will be always first 15 characters.for comparing we will consider this only 20220329_141153.
but while write final output it will be 20220329_141153_ADU_INPUT

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采纳的回答

Santosh Biradar
Santosh Biradar 2022-8-30
for i=1:length(chkDataFileName)
for j=1:length(Newlyaddednames)
inpSTR=char(chkDataFileName(i));
newSTR=char(Newlyaddednames(j));
if strfind(newSTR,inpSTR(1:end-10))
BLF_Name=chkDataFileName(i)
SnapTime = newSTR(17:end)
end
end
end

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