mixing audios according to array value
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hi i have the following code which mixes two audios and plots them :
Fs = 44100;
[y,Fs] = audioread("sound and 1000 new.wav");
[x,Fs] = audioread("160 hz.wav");
mix = y+x;
sound(mix,Fs)
Nsamps = length(mix);
t = (1/Fs)*(1:Nsamps)
y_fft = abs(fft(mix));
y_fft = y_fft(1:Nsamps/2);
f = Fs*(0:Nsamps/2-1)/Nsamps;
figure
plot(f, y_fft)
xlim([0 5000])
xlabel('Frequency (Hz)')
ylabel('Amplitude')
the values of y and x are x = 192000 and y = 192000
now i create a simple sine tone by the following code:
Fs = 44100;
dt = 1/Fs;
StopTime = 3
t = (0:dt:StopTime-dt);
Fc = 1000;
A = 1;
z = A*sin(2*pi*Fc*t);
sound(z,Fs)
the value of z is
as we can see Z is different than X and Y although they are all 3 seconds so i cant mix them, how can i generate a simple sine tone with tha value of Z similar to X and Y so im able to mix them?
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Mathieu NOE
2022-9-1
hello
the simplest trick here is to first generate z with the same dimension (length) as x and y
use the initial t vector already defined for x / y in the first section of your code
then simply force the values of z for t > StopTime to zero
Fs = 44100; % nb : already defined in first section, no need to duplicate this line
dt = 1/Fs;
StopTime = 3
% t = (0:dt:StopTime-dt); not used here , use t = (1/Fs)*(1:Nsamps)
% already defined in first section
Fc = 1000;
A = 1;
z = A*sin(2*pi*Fc*t);
z(t>StopTime) = 0;
sound(z,Fs)
5 个评论
Mathieu NOE
2022-9-2
ok - got it , simply changed a few things to make sure it works for any number of channels
I added so normalisation of the output otherwise you may clip (wav export assumes your total signal does not exceed +/- 1 range !)
%% my test files
% [y,Fs] = audioread("test_voice_mono.wav"); % mono
[y,Fs] = audioread("test_voice.wav"); % stereo
% Fs = 44100; % why ? - do not overwritte Fs obtained from line above
dt = 1/Fs;
StopTime = 3;
Nsamps = length(y);
t = (1/Fs)*(1:Nsamps)'; % !! NB : transpose t to make it col oriented like y
Fc = 1000;
A = 1;
z = A*sin(2*pi*Fc*t); % is now also col oriented like y
z(t>StopTime) = 0;
mix = y+z;
% important : normalize output amplitude to avoid clipping
mix = mix./(max(abs(mix)));
sound(mix,Fs)
Mathieu NOE
2022-9-2
hello again
yeap - finally we converged more or less to the same solution !
still don't forget to normalize mix output to stay within +/- 1 range !
all the best
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