exit from loop
显示 更早的评论
hi, in the following code,I need when mat(k,2)=map(j,2)exit of loop.
for j=1:i
for k=1:L
if map(j,1)==mat(k,2)
mat(k,2)=map(j,2);
end
end
end
回答（1 个）
Walter Roberson
2011-10-12
leave_early = false;
for j=1:i
if leave_early; break; end
for k=1:L
if map(j,1)==mat(k,2)
mat(k,2)=map(j,2);
leave_early = true;
break
end
end
end
2 个评论
Andrei Bobrov
2011-10-12
[i1,j1] = find(bsxfun(@eq,map(:,1)',mat(:,2)),1,'first');
mat(i1,2)=map(j1,2);
Jan
2011-10-12
@Andrei: Please post this as an answer.
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2011-10-12
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