# I can't figure out why am not getting a plot on my code

2 次查看（过去 30 天）
John2022-10-25

Write a MATLAB code for plot original and transformation function of
function y=ga(t);
y = -2*(t<=-1)+2*t.*(-1<t&t<=1)+(3-t.^2).*(1<t&t<=3)-6*(t>3);
figure;
tmin=-3;tmax=8;N=100;
dt=(tmax-tmin)/N; t=tmin+dt*[0:N]';
g0=ga(t);g1=-3*ga(4-t);
subplot(2,1,1);p=plot(t,g0,'k');set(p,'LineWidth',2);grid;
ylabel('g(t)');
title('(a)-g(t)=-2,t<-1,2t,-13')
subplot(2,1,2);p=plot(t,g1,'k');set(p,'LineWidth',2);grid;
xlabel('t');ylabel('-3g(4-t');

### 回答（1 个）

Chunru 2022-10-25
If you put the script and local function ga in the same file, then local functions should be placed at the end of the files as shown below. You can also put the local function in a separate file,
figure;
tmin=-3;tmax=8;N=100;
dt=(tmax-tmin)/N; t=tmin+dt*[0:N]';
g0=ga(t);g1=-3*ga(4-t);
subplot(2,1,1);p=plot(t,g0,'k');set(p,'LineWidth',2);grid;
ylabel('g(t)');
title('(a)-g(t)=-2,t<-1,2t,-13')
subplot(2,1,2);p=plot(t,g1,'k');set(p,'LineWidth',2);grid;
xlabel('t');ylabel('-3g(4-t');
function y=ga(t);
y = -2*(t<=-1)+2*t.*(-1<t&t<=1)+(3-t.^2).*(1<t&t<=3)-6*(t>3);
end

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