Putting certain blocks of numeric array data into its own cell each in a cell array. - tried num2cell and an index method to do this...

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Thom 2011-10-15

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I need to put certain blocks of numeric array data into its own cell each in a cell array.

I have a 1364 rows by 16 columns array. I want to place the first lot of 11 rows of data into the first cell (to result in 176 values in the first cell) , then the second lot of 11 rows into the second cell (the next 176 values here) , the third lot of 11 into the third cell and so on. for example: from : array = AAAAA; AAAAA; BBBBB; BBBBB; CCCCC; CCCCC; ...... I need: cell array(1) = AAAAA; AAAAA and so on....

Because it is a 1364 rows grid, there should then be (1364/11) = 124 cell collumns along only one row in the cell array.

I have used the num2cell command to try and do this, and an index method to do it too, but neither seem to get exactly what I need. How should these two methods be written to get what I need?

I'm new to matlab so apologies if this is a really basic question. thanks

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Jan 2011-10-15

It is easier to answer, if you post your code. Then we could fix the error, but without your code, we have to write it from scratch.

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Answer 1

Jan 2011-10-15

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https://ww2.mathworks.cn/matlabcentral/answers/18355-putting-certain-blocks-of-numeric-array-data-into-its-own-cell-each-in-a-cell-array-tried-num2cel#answer_24663

在 MATLAB Online 中打开

A = rand(1364, 16);
B = reshape(A, 11, 1364/11, 16);
B = permute(B, [1, 3, 2]);
C = num2cell(B, [1, 2]);
C = C(:);

But inside NUM2CELL you have a FOR loop also, so it might be more efficient to write it explicitely:

C = cell(124, 1);  % Pre-allocate
B = reshape(A, 11, 1364/11, 16);
for iC = 1:numel(C)
  C{iC} = reshape(B(:, iC, :), 11, 16);
end

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Thom 2011-10-15

Thanks very much! That helped so much! I will also remember to write in my code next time, In this instance I just didnt bother since I didnt have much confidence in them. What is C = C(:);?

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