How to implement more steps in mathwork coding?
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fun [ …… 0ut2 …. ]= mainfun [………………….]
iteration=0
while iteration<maxiterationno
some parameter and their calculation
iteration=iteration+1
[ ]=subfun1 [];
[ ,out2 ]= subfun2[];
if iteration == 1
% at the first iteration save the result
B = out2;
else
% for all other iterations, check if the new result is bigger
if sum( B(:,c) ) < sum( out2(:,c) )
% if so break the loop
break
end
end
Newoutput=out2(1:10,:)
end
end
By doing this I am getting my generation number with my expected value ,but i want to do another further steps like ,
when my previous condition match that time i want to keep the value of the out2 and want to do another few iteration and everytime i want to compare with the new iteration value with the out2 value .
like maybe i got the expected out2 value at iteration number 100 , so i will keep the value of out2 as constant and will do the next few iteration and everytime i will compare the value with different iteration means 101th iteration with 100 iteration or 102 iteration value with 100 iteration value where out2 value will be constant after 100th iteration when the first condition will match and then it will continue maybe another 3 to 5 iteration .
then i want to stop my iteration .
Thank you in advance .
0 个评论
采纳的回答
Image Analyst
2022-11-14
编辑:Image Analyst
2022-11-14
@Akash Pal are you sure you're incrementing iteration immediately upon entering the while? And if you've extended the number of iterations, make sure you don't extend it again.
function [ …… out2 … ]= mainfun […………………]
iteration=0;
maxiterationno = 1000;
alreadyExtended = false;
while iteration < maxiterationno
iteration = iteration + 1; % ADD THIS LINE!
if iteration == 1 % At the first iteration save the result
B = out2;
else % For all other iterations, check if the new result is bigger
if sum( B(:,c) ) < sum( out2(:,c) )
% break - no, don't break the loop, but:
% Tell it to continue for another 5 iterations.
if ~alreadyExtended % ADD THIS LINE!
% If we have not yet extended it 5 iterations yet, do so now.
maxiterationno = iteration + 5;
alreadyExtended = true; % Flag it so we don't keep extending the max iteration number.
end
B = out2;
end
end
end
2 个评论
Image Analyst
2022-11-15
OK, since this prevents it from extending the maximum number of iterations forever, and lets you continue the loop 5 beyond the normal stopping point, could you click the "Accept this answer" link? Thanks in advance. 🙂
更多回答(1 个)
Jan
2022-11-11
编辑:Jan
2022-11-11
Maybe:
fun [ …… 0ut2 …. ]= mainfun [………………….]
iteration=0
while iteration < maxiterationno
...
if iteration == 1 % at the first iteration save the result
B = out2;
else % for all other iterations, check if the new result is bigger
if sum( B(:,c) ) < sum( out2(:,c) )
% break - no, don't break the loop, but:
maxiterationno = iteration + 5;
B = out2;
end
end
end
7 个评论
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