How to implement more steps in mathwork coding?

Question

Akash Pal 2022-11-11

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1848508-how-to-implement-more-steps-in-mathwork-coding

评论： Akash Pal 2022-11-16

fun [ ……                  0ut2  ….   ]= mainfun [………………….]
iteration=0
while  iteration<maxiterationno
some parameter and their calculation
iteration=iteration+1
[                               ]=subfun1 [];
[                            ,out2    ]= subfun2[];
if iteration == 1
        % at the first iteration save the result
        B = out2;
    else
        % for all other iterations, check if the new result is bigger
        if sum( B(:,c) ) < sum( out2(:,c) )
            % if so break the loop
            break
        end
    end
Newoutput=out2(1:10,:)
end
end

By doing this I am getting my generation number with my expected value ,but i want to do another further steps like ,

when my previous condition match that time i want to keep the value of the out2 and want to do another few iteration and everytime i want to compare with the new iteration value with the out2 value .

like maybe i got the expected out2 value at iteration number 100 , so i will keep the value of out2 as constant and will do the next few iteration and everytime i will compare the value with different iteration means 101th iteration with 100 iteration or 102 iteration value with 100 iteration value where out2 value will be constant after 100th iteration when the first condition will match and then it will continue maybe another 3 to 5 iteration .

then i want to stop my iteration .

Thank you in advance .

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Answer 1

Image Analyst 2022-11-14

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1848508-how-to-implement-more-steps-in-mathwork-coding#answer_1099338

编辑：Image Analyst 2022-11-14

在 MATLAB Online 中打开

@Akash Pal are you sure you're incrementing iteration immediately upon entering the while? And if you've extended the number of iterations, make sure you don't extend it again.

function [ ……  out2  … ]= mainfun […………………]
iteration=0;
maxiterationno = 1000;
alreadyExtended = false;
while  iteration < maxiterationno
    iteration = iteration + 1; % ADD THIS LINE!
    if iteration == 1   % At the first iteration save the result
        B = out2;
    else                % For all other iterations, check if the new result is bigger
        if sum( B(:,c) ) < sum( out2(:,c) )
            % break - no, don't break the loop, but:
            % Tell it to continue for another 5 iterations.
            if ~alreadyExtended % ADD THIS LINE!
                % If we have not yet extended it 5 iterations yet, do so now.
                maxiterationno = iteration + 5;
                alreadyExtended = true; % Flag it so we don't keep extending the max iteration number.
            end
            B = out2;
        end
    end
end

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Akash Pal 2022-11-15

yes

Image Analyst 2022-11-15

OK, since this prevents it from extending the maximum number of iterations forever, and lets you continue the loop 5 beyond the normal stopping point, could you click the "Accept this answer" link? Thanks in advance. 🙂

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Answer 2

Jan 2022-11-11

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1848508-how-to-implement-more-steps-in-mathwork-coding#answer_1097048

编辑：Jan 2022-11-11

在 MATLAB Online 中打开

Maybe:

fun [ ……                  0ut2  ….   ]= mainfun [………………….]
iteration=0
while  iteration < maxiterationno
    ...
    if iteration == 1   % at the first iteration save the result
        B = out2;
    else                % for all other iterations, check if the new result is bigger
        if sum( B(:,c) ) < sum( out2(:,c) )
            % break - no, don't break the loop, but:
            maxiterationno = iteration + 5;
            B = out2;
        end
    end
end

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Jan 2022-11-15

Yes. Exactly this is done by my code, isn't it?

Akash Pal 2022-11-16

Yes ,the code is also do the same ,but in my case i got some error when i am trying to change some parameter .Thank you for your help to get the idea how to implement it .

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