Counting occurrence of elements in an array
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How would I go about counting the occurrence of elements in an array including elements that may not be in the array.
For example if x = [2 3 2 4 5 6 8 2 9 5], I would like to produce an array that has the frequency of each element from 1 to 10 so it'd be output = [0 3 1 1 2 1 0 1 1 0]
Thanks
采纳的回答
Star Strider
2015-3-25
编辑：Star Strider
2015-3-25
Use the hist function:
x = [2 3 2 4 5 6 8 2 9 5];
binc = [1:10];
counts = hist(x,binc);
result = [binc; counts]
produces:
result =
1 2 3 4 5 6 7 8 9 10
0 3 1 1 2 1 0 1 1 0
更多回答（1 个）
This works....
x= [2 3 2 4 5 6 8 2 9 5]
for index=1:length(x)
y(index)= sum(x==index);
end
y
produces
x =
2 3 2 4 5 6 8 2 9 5
y =
0 3 1 1 2 1 0 1 1 0
1 个评论
Katherine May
2024-10-4
This also works for array items that aren't numbers!
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