Loop cycle to input similar txt files

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Hello everybody, I'm trying to solve a problem to input data. I have 39 txt files that have similar names. The name has two variables and I'd like to import the data as a function that contains those two numbers.
So a general name of the file is "CV_d{m}_die{i}", i goes from 1 to 13 and m is equal to 100, 200 or 400.
I've done this
input_folder = 'folder'
files = dir(fullfile(input_folder, "*.txt"))
file_paths = fullfile({files.folder}, {files.name})
for i = 1:13
for m = [100 200 400]
Data_{m}_{i} = dlmread("CV_d{m}_die{i}.txt", ',', 4, 0)
end
end
So my idea was to do this loop and get 39 Data_m_i. Like Data_100_1, Data_200_1, Data_400_1, and then i=2...
But I get an error that says that the file could not be opened because there's no such file or directory.

采纳的回答

Jan
Jan 2022-12-8
编辑:Jan 2022-12-8
Data_{m}_{i} is your invention an no valid Matlab syntax. This is not the way programming works.
Matlab does not magically modifiy the string "CV_d{m}_die{i}.txt" to what you want. Why do you assume that the curly braces let Matlab inserts the numbers?
Use a command to create a specific string:
dlmread(sprintf('CV_d%d_die%d.txt', m, i), ',', 4, 0);
Why do you create a list of filenames, which is not used?
Data_1_100 is a bad choice for the name of a variable. Hiding information in the name of a variable makes it hard to access it later. Store such important information such, that you can use the later:
k = 0;
for i = 1:13
for m = [100 200 400]
file = fullfile(folder, sprintf('CV_d%d_die%d.txt', m, i));
k = k + 1;
Data(k).value = dlmread(file, ',', 4, 0);
Data(k).m = m;
Data(k).i = i;
end
end
Hiding information in names of variables is a typical design error made by beginners. See this exhaustive explanation, why other methods should be preferred: TUTORIAL: Why Variables Should Not Be Named Dynamically (eval)
  8 个评论
Simone
Simone 2022-12-10
Sorry I didn't understand that I had to remove those first lines, yes it perfectly works.
Doing so I get a table that has the imported data associated with each m and i value. But if I want to work with the second column of the data associated to m=100 and i=2 for example, how am I supposed to specify that particular data-file in the script?
Clicking to see the table of a particular imported data says the name Data with a number on parenthesis
Jan
Jan 2022-12-10
"Sorry I didn't understand that I had to remove those first lines" - I do not understand. There is no need to remove the first lines, they are just useless - as long as the folder name is set correctly.
If you want the values for m=3 and i = 200:
m_list = [Data.m];
i_list = [Data.i];
value = Data(m_list == 3 & i_list == 200).value;
Now you can run a loop easily over all data.

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更多回答(1 个)

Image Analyst
Image Analyst 2022-12-10
编辑:Image Analyst 2022-12-10
Use the first snippet, not the second method like you're doing.
Avoid the problem of missing files by using dir() to get only files that actually exist.
% Specify the folder where the files live.
input_folder = 'C:\Users\yourUserName\Documents\My Pictures';
% Check to make sure that folder actually exists. Warn user if it doesn't.
if ~isfolder(input_folder)
errorMessage = sprintf('Error: The following folder does not exist:\n%s\nPlease specify a new folder.', myFolder);
uiwait(warndlg(errorMessage));
input_folder = uigetdir(); % Ask for a new one.
if input_folder == 0
% User clicked Cancel
return;
end
end
% Get a list of all files in the folder with the desired file name pattern.
filePattern = fullfile(input_folder, '*.txt'); % Change to whatever pattern you need.
theFiles = dir(filePattern);
for k = 1 : length(theFiles)
baseFileName = theFiles(k).name;
fullFileName = fullfile(theFiles(k).folder, baseFileName);
fprintf(1, 'Now reading %s\n', fullFileName);
% Now do whatever you want with this file name,
% such as parsing it to get i and m.
% Parse 'CV_dm_diei.txt'
underlineLocations = strfind(baseFileName, '_');
m = str2double(baseFileName(underlineLocations(1) + 2 : underlineLocations(2) - 1));
dieIndex - strfind(baseFileName, '_die');
i = str2double(baseFileName(dieIndex + 4: end - 4));
% Read in the data (code below is not mine or from the FAQ).
Data(k).value = dlmread(fullFileName, ',', 4, 0);
Data(k).m = m;
Data(k).i = i;
end

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