Using while loops in matrices

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Olabayo
Olabayo 2022-12-17
I am trying to use while loop to change the diagonal entries of a square matrix rand(10) to 1, and other entries to zero
This code below is changing the whole entries to 1, i am stucked.
m= 1:10
n= 1:10
A = rand(10)
B = size (A)
while m==n
A(m,n) = 1;
if not (m==n)
A(m,n) = 0;
end
break
end
A

回答(1 个)

Pin-Hao Cheng
Pin-Hao Cheng 2022-12-17
Let me know if this is what you are looking for. Happy to answer any further questions!
A = rand(10)
A = 10×10
0.1406 0.9234 0.5213 0.0271 0.2317 0.3967 0.3776 0.4847 0.3080 0.0222 0.4363 0.4473 0.2888 0.3199 0.6071 0.3528 0.3311 0.5584 0.4040 0.2190 0.2656 0.6738 0.6987 0.3731 0.8456 0.9905 0.1035 0.4882 0.4701 0.2163 0.0655 0.9590 0.1978 0.6575 0.6074 0.2159 0.2553 0.3445 0.9210 0.6419 0.8856 0.9335 0.8339 0.5396 0.2503 0.0700 0.4051 0.7461 0.3052 0.1634 0.4934 0.4743 0.6264 0.2365 0.6042 0.4961 0.4183 0.7427 0.0465 0.3843 0.2964 0.5497 0.6846 0.4194 0.2852 0.9456 0.7047 0.9608 0.4107 0.6736 0.7785 0.3134 0.1016 0.5672 0.2764 0.7794 0.3809 0.2773 0.2288 0.1847 0.6817 0.5795 0.6303 0.4710 0.6249 0.1779 0.3139 0.5706 0.5860 0.4254 0.6862 0.1720 0.4387 0.9392 0.0916 0.3381 0.4475 0.3649 0.5224 0.7542
for m = 1:10 % loop through rows
for n = 1:10 % loop through columns
if m == n % check if it's diagonal el
A(m,n) = 1;
else
A(m,n) = 0;
end
end
end
A
A = 10×10
1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1
  7 个评论
Jan
Jan 2022-12-17
The pattern:
if m == n
A(m,n) = 1;
else
A(m,n) = 0;
end
can be abbreviated in general to:
A(m, n) = (m == n);
Walter Roberson
Walter Roberson 2022-12-17
The whole thing abbreviates to a call to eye() and size()

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