How to add rows to the matrix

6 次查看（过去 30 天）
EK
EK 2022-12-17
评论： EK 2022-12-18
Hallo,
I have a matrix of 6 columns (an example attached here) that are : trials, stimulus IDs, Hit, Miss, CR, FA.
Hit, Miss, CR, FA colomns are coded as a 0 and 1 but the FA column has sometimes numbers larger than 1 that indicates number of repeated trials that are not included in to the matrix. I need correct this and everywhere when FA colomn has number > 1 replace it with repeated rows in a number of repeats. For example, in given example in the trial 6 FA has number of repeats 5. I need to replace it with 5 consequentive rows after 6th trial (trials 7-11) in which stimulus is the same, Hit, Miss, CR, would have 0 and FA column 1. Same is for trial 20 (add 3 repeated trials) and 29 (add 2 repeated trials) etc
Can anyone help with this?
  1 个评论
Jan
Jan 2022-12-17
You have attached an Excel file. Is importing this file a part of the problem? What is the wanted output? A Matlab matrix or another Excel file?
Does "raws" mean "rows"?

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Torsten
Torsten 2022-12-17
编辑：Torsten 2022-12-18
Ran in:
Like this ?
A = [1 4 0 0 1 0
2 3 0 1 0 0
3 3 0 1 0 0
4 4 0 0 1 1
5 3 0 1 0 0
6 4 0 0 1 5
7 3 0 1 0 0
8 3 1 0 0 0
9 4 0 0 1 0
10 4 0 0 0 1];
B = [];
irow = 0;
for i = 1:size(A,1)
B(irow+1,:) = [irow+1,A(i,2:6)];
irow = irow + 1;
trials = A(i,6);
if trials ~= 0 && trials ~= 1
for j = 1:trials
B(irow+j,:) = [irow+j 0 0 0 0 1];
end
irow = irow + trials;
end
end
B(1:10,:)
ans = 10×6
1 4 0 0 1 0 2 3 0 1 0 0 3 3 0 1 0 0 4 4 0 0 1 1 5 3 0 1 0 0 6 4 0 0 1 5 7 0 0 0 0 1 8 0 0 0 0 1 9 0 0 0 0 1 10 0 0 0 0 1
B(11:15,:)
ans = 5×6
11 0 0 0 0 1 12 3 0 1 0 0 13 3 1 0 0 0 14 4 0 0 1 0 15 4 0 0 0 1
  6 个评论
显示 4更早的评论
Torsten
Torsten 2022-12-18
Ran in:
A = [1 4 0 0 1 0
2 3 0 1 0 0
3 3 0 1 0 0
4 4 0 0 0 1
5 3 0 1 0 0
6 4 0 0 0 5
7 3 0 1 0 0
8 3 1 0 0 0
9 4 0 0 1 0
10 4 0 0 0 2
11 4 0 0 1 0
12 3 0 1 0 0
13 3 0 1 0 0
14 4 0 0 0 1];
B = [];
irow = 0;
for i = 1:size(A,1)
trials = A(i,6);
if trials ~= 0 && trials ~= 1
for j = 1:trials
B(irow+j,:) = [irow+j,A(i,2:5),1];
end
irow = irow + trials;
else
B(irow+1,:) = [irow+1,A(i,2:6)];
irow = irow + 1;
end
end
B(1:10,:)
ans = 10×6
1 4 0 0 1 0 2 3 0 1 0 0 3 3 0 1 0 0 4 4 0 0 0 1 5 3 0 1 0 0 6 4 0 0 0 1 7 4 0 0 0 1 8 4 0 0 0 1 9 4 0 0 0 1 10 4 0 0 0 1
B(11:end,:)
ans = 9×6
11 3 0 1 0 0 12 3 1 0 0 0 13 4 0 0 1 0 14 4 0 0 0 1 15 4 0 0 0 1 16 4 0 0 1 0 17 3 0 1 0 0 18 3 0 1 0 0 19 4 0 0 0 1
EK
EK 2022-12-18
Thank you so much! You are amazing!

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Startup and Shutdown 的更多信息

标签

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by