How do i add a time vector to a existing table?

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I have a set of given data but they do not include a time. I am trying to add a time (Tijd) vector but if i add a time vector, i get the messages that vectors must be the same length.
The data is a set amount of measurements (4001) but with a sample rate of 50Hz. I ofcourse want the time to be in seconds. So I thought I would make the steps in the graph steps of 81 because 4001/50 ≈ 81. But even without the steps it still gives me the error of vectors must be the same length.
Any and all help is appreciated!
clear all
close all
clc
load('ACE2-opdracht-2-persoonlijk.mat', 'meetdata');
A = meetdata;
Motortoerental = A (:,1);
Stuurspanning = A (:,2);
Tijd = 1:81:4001;
figure;
subplot(1,2,1)
plot(Tijd, Motortoerental); hold on
xlabel('Tijd(s)')
ylabel('Toerental(Omw/min)')
grid;
subplot(1,2,2)
plot(Tijd, Stuurspanning); hold on
xlabel('Tijd(s)')
ylabel('Stuurspanning(V)')
grid;
  2 个评论
Stephen23
Stephen23 2022-12-21
Avoiding the possibility of floating point issues with the last value:
(0:4000)./50
ans = 1×4001
0 0.0200 0.0400 0.0600 0.0800 0.1000 0.1200 0.1400 0.1600 0.1800 0.2000 0.2200 0.2400 0.2600 0.2800 0.3000 0.3200 0.3400 0.3600 0.3800 0.4000 0.4200 0.4400 0.4600 0.4800 0.5000 0.5200 0.5400 0.5600 0.5800

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采纳的回答

Torsten
Torsten 2022-12-21
Shouldn't it be
Tijd = (0:0.02:4000*0.02).'
?
  3 个评论
Torsten
Torsten 2022-12-21
Your vector Tijd must have 4001 elements in order to plot Tijd against the other two arrays Motortoerental and Stuurspanning.
You said the measurements are every 0.02 s - thus
Tijd = (0:0.02:4000*0.02).'

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