To find intersection, and to calculate the area between two curves for two functions.

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VIDHYA HARINI
VIDHYA HARINI 2023-1-7
评论： Walter Roberson 2023-1-8
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Hi everyone, kindly please help me in solving this problem. I am new to this matlab. So I am not really sure how to do this.
Hoping for a step-by-step answer.
Let f(x) = e^x - 1 and g(x) = 1 - x^2 for x ∈ [0; 1]. Draw the graphs of the two functions f and g, determine the point of intersection z of the two graphs and calculate the area of the region between the two graphs in [0; z].
Thank you in advance.

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Sulaymon Eshkabilov
编辑：Sulaymon Eshkabilov 2023-1-7
Ran in:
Step 1. Calculation the two functions
x = linspace(0, 1, 200);
f = exp(x)-1;
g = 1-x.^2;
Step 2. Plot the calculated f(x) and g(x) points
plot(x, f, 'b-', x, g, 'r', LineWidth=2), grid on
xlabel('$x$', 'interpreter', 'latex')
ylabel('$f(x), \ g(x)$', 'interpreter', 'latex')
title 'Area between two curves', hold on
Step 3. Find the intersection
[xi,yi] = polyxpoly(x,f,x,g);
mapshow(xi,yi,'DisplayType','point','Marker','o', 'MarkerFaceColor', 'c', 'MarkerSize', 9)
Step 4. Compute the area between the two curves
AREA = trapz(x,f)-trapz(x,g)
AREA = 0.0516
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Walter Roberson
Walter Roberson 2023-1-8
Ran in:
@Sulaymon Eshkabilov
The area "between" the two curves is the sum:
  • area of (higher one minus lower one) between 0 and intersection point; plus
  • area of (new higher one minus new lower one) between intersection point and 1.
Which can also be expressed as the absolute value of the difference in the functions.
The calculation you did is the plain difference between the functions -- and the difference goes negative when the functions intersect.
syms t
AREA = int(abs((exp(t)-1) - (1-t.^2)), 0, 1)
AREA = 
vpa(AREA)
ans = 
0.67464615778033102610566089193666

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