convert 1x20 double struct into a vector containing 20 values

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Kick Greven 2023-2-1

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https://ww2.mathworks.cn/matlabcentral/answers/1904755-convert-1x20-double-struct-into-a-vector-containing-20-values

评论： Jan 2023-2-1

I have a struct which is '1x20 double'

When I plot this, I get these 20 y-values plotted from x=1 to x=20

However, I need to be able to plot all of these values on the same x coordinate.

Nothing I do works because it is in a struct.

struct2table/struct2cell do not work.

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Kick Greven 2023-2-1

Well It's a 1x307 struct with 10 fields that I extracted 20 values from into a new variable via indexing. I guess this variable is not a struct then? The code generating the struct is 400+ lines long so I decided not to share. I think that the variable wasn't a struct after all, but I got very confused about the way that it didn't look like a vector or matrix so I didn't know what to do.

Jan 2023-2-1

@Kick Greven: You can simply check, what the type is using the class() command.

"a 1x307 struct with 10 fields that I extracted 20 values from into a new variable via indexing." - Please note, that you might know, what this means, but a reader can have a faint idea aboud the corresponding procedure only. This is the hard part of asking question: considering that the readers know as much as a rubber duck about the problem while you hope, that they can solve it. :-)

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Answer 1

Jan 2023-2-1

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https://ww2.mathworks.cn/matlabcentral/answers/1904755-convert-1x20-double-struct-into-a-vector-containing-20-values#answer_1161565

在 MATLAB Online 中打开

With wild guessing:

S.y = rand(1, 20); % Is this equivalent to your struct?

plot(S.y); % Is this the way your get a plot?

% And you want this:

x = 2;

figure;

plot(x, S.y, 'o')

Remember, that plot(x, S.y) without specifying the marker will not show anything, because lines appear only, if their length is greater than 0, what is not true for single points.

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Kick Greven 2023-2-1

This actually looks like it might be a perfect solution. Thank you so much. I have been searching for the wrong solution for about an hour now. Thanks a lot.

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