perform interpolation each row of a matrix

6 次查看(过去 30 天)
i have a matrix A with one million rows, and each row is monotonic increase. the value in each row is x.
The interpolation is perform to obtain one million yi for each row given a constant xi value (xi is the same for each row) and given an array y (y is also the same for each row). is there an efficient way to get yi other than using loop.
right now i have to use loop like this:
for i = 1:1e6
yi(i) = interpi(A(i,:), y, xi);
end

回答(1 个)

Fangjun Jiang
Fangjun Jiang 2023-2-3
编辑:Fangjun Jiang 2023-2-3
You can use interp1() directly for this without for-loop.
x=1:10;
A=(1:10)'+(1:10);
xi=5;
y=interp1(x,A',xi)
y = 1×10
6 7 8 9 10 11 12 13 14 15
  5 个评论
wangm
wangm 2023-2-3
wait, you did not answer my question. in my question, matrix A is x, but you matrix A is y.
Fangjun Jiang
Fangjun Jiang 2023-2-3
I was taking some guesses on your question. Now you need to clarify these. "the value in each row is x", "in my question, matrix A is x", "but you matrix A is y".
The best way is to provide a complete numerical example, including the value for x, xi, y.
You don't need to provide one million rows. Three row is sufficient.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

产品


版本

R2011b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by