How to change a bit from 0 to 1.

Question

barath manoharan 2023-2-15

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1913075-how-to-change-a-bit-from-0-to-1

回答： Steven Lord 2023-2-15

iam having 5 decimal numbers , i have converted this 5 decimal nos to binary numbers to perform some mathematical operations.

A consists of five decimal numbers and B consists of A's corresponding binary representation. Now each element has to be compared against the remaining elements. first element and last element differs by one bit so the expected output is 10111 similarly 2nd element and last element differs by 1 bit so the expected output is 10111. the remaining 2 elements cannot be merged because they have more than 1 dissimilar bit when compared against remaining elements. The expected output is 10111,1100,1011. Thank you in advance.

For example:

A = [7;19;12;11;23]

B = [00111;10011;01100;01011;10111]

Expected Output :

C = [10111;01100;01011]

3 个评论
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Dyuman Joshi 2023-2-15

So you want to compare 1st and nth element, 2nd and n-1 th element and 3rd and n-2 th element and so on?

Jan 2023-2-15

编辑：Jan 2023-2-15

The same problem occurred already in the forum. "B = [00111;10011;01100;01011;10111]" is not a binary array. "00111" is the decimal number onehundreteleven.

So please explain, in which format the values are really represented.

If you really use decimal numbers to represent binary values, this is a surprisingly bad idea, which impedes easy solutions.

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Answer 1

Steven Lord 2023-2-15

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1913075-how-to-change-a-bit-from-0-to-1#answer_1172455

在 MATLAB Online 中打开

A = [7;19;12;11;23]
A = 5×1
     7
    19
    12
    11
    23
B = bitset(A, 5)
B = 5×1
    23
    19
    28
    27
    23
binA = dec2bin(A, 5)
binA = 5×5 char array
    '00111'
    '10011'
    '01100'
    '01011'
    '10111'
binB = dec2bin(B, 5)
binB = 5×5 char array
    '10111'
    '10011'
    '11100'
    '11011'
    '10111'