Why is my function not working?
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I am very new to MATLAB, as in, started two days ago because I'm trying to translate some code from mathematica.
For context x0 = 1 and x,x2 are undefined in this function
function [f355] = f355(x,x0,x2)
%UNTITLED4 Summary of this function goes here
% Detailed explanation goes here
if x >= 0
f355 = (Omega00)*sqrt((1)+((Lambda355*x)/(pi*(Omega00))^2));
elseif (x<=(x2+x1+x0))&&(x>=x0)
f355 = NewBWaist(Omega00,x0,f,Lambda355)*sqrt((1)+(Lambda355*(x-x0-x1)/(pi(Omega01)^2)));
else x >= (x0+x1+x2)
f355 = NewBWaist(NewBWaist(Omega00,x0,f1U,Lambda355),x2,f2U,Lambda355)*sqrt((Lambda355(x-sumxU))/(pi*(Omega02)^2));
end
When I run "f355(10,1,20)" I get an error
"Index in position 1 exceeds array bounds. Index must not exceed 1.
Error in m118codeInprogress (line 111)
f355(10,1,20)"
Any advice would be most welcome. Thanks.
3 个评论
Dyuman Joshi
2023-2-24
编辑：Dyuman Joshi
2023-2-24
There are un-defined variables in your code - Omega00, Lambda355, etc. Please specify their values.
Also, do not use the same name for function and a variable, as it overwrites the assignment.
Theobold
2023-2-24
Dyuman Joshi
2023-2-24
Rename your output variable name and run your code. As other functions are working properly, your code should work after the correction as well.
采纳的回答
Avoid using the name of the function as name of the output. This is confusing only.
Which is the failing line? In this line f355 is used as a variable, not as a function.
See this example:
sin(0.1) % Fine
sin = 15; % Now sin is a variable
sin(0.1) % Error: 0.1 is no valid index
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