Why is my function not working?

10 次查看(过去 30 天)
I am very new to MATLAB, as in, started two days ago because I'm trying to translate some code from mathematica.
For context x0 = 1 and x,x2 are undefined in this function
function [f355] = f355(x,x0,x2)
%UNTITLED4 Summary of this function goes here
% Detailed explanation goes here
if x >= 0
f355 = (Omega00)*sqrt((1)+((Lambda355*x)/(pi*(Omega00))^2));
elseif (x<=(x2+x1+x0))&&(x>=x0)
f355 = NewBWaist(Omega00,x0,f,Lambda355)*sqrt((1)+(Lambda355*(x-x0-x1)/(pi(Omega01)^2)));
else x >= (x0+x1+x2)
f355 = NewBWaist(NewBWaist(Omega00,x0,f1U,Lambda355),x2,f2U,Lambda355)*sqrt((Lambda355(x-sumxU))/(pi*(Omega02)^2));
end
When I run "f355(10,1,20)" I get an error
"Index in position 1 exceeds array bounds. Index must not exceed 1.
Error in m118codeInprogress (line 111)
f355(10,1,20)"
Any advice would be most welcome. Thanks.
  3 个评论
Theobold
Theobold 2023-2-24
Apologies,
Omega00= 3.5
Lambda355= 0.000355
The rest of the variables are themselves defined by other functions with yet more variables. The other functions are all working though.
Dyuman Joshi
Dyuman Joshi 2023-2-24
Rename your output variable name and run your code. As other functions are working properly, your code should work after the correction as well.

请先登录,再进行评论。

采纳的回答

Jan
Jan 2023-2-24
移动:Jan 2023-2-24
Avoid using the name of the function as name of the output. This is confusing only.
Which is the failing line? In this line f355 is used as a variable, not as a function.
See this example:
sin(0.1) % Fine
sin = 15; % Now sin is a variable
sin(0.1) % Error: 0.1 is no valid index
  1 个评论
Theobold
Theobold 2023-2-24
Right I see, I ran a calculation earlier (since deleted) with f355= so I guess it's now assigned as a variable?
Thanks for the advice.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Operating on Diagonal Matrices 的更多信息

产品


版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by