Why is my function not working?

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Theobold
Theobold 2023-2-24
评论： Dyuman Joshi 2023-2-24
I am very new to MATLAB, as in, started two days ago because I'm trying to translate some code from mathematica.
For context x0 = 1 and x,x2 are undefined in this function
function [f355] = f355(x,x0,x2)
%UNTITLED4 Summary of this function goes here
% Detailed explanation goes here
if x >= 0
f355 = (Omega00)*sqrt((1)+((Lambda355*x)/(pi*(Omega00))^2));
elseif (x<=(x2+x1+x0))&&(x>=x0)
f355 = NewBWaist(Omega00,x0,f,Lambda355)*sqrt((1)+(Lambda355*(x-x0-x1)/(pi(Omega01)^2)));
else x >= (x0+x1+x2)
f355 = NewBWaist(NewBWaist(Omega00,x0,f1U,Lambda355),x2,f2U,Lambda355)*sqrt((Lambda355(x-sumxU))/(pi*(Omega02)^2));
end
When I run "f355(10,1,20)" I get an error
"Index in position 1 exceeds array bounds. Index must not exceed 1.
Error in m118codeInprogress (line 111)
f355(10,1,20)"
Any advice would be most welcome. Thanks.
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Theobold
Theobold 2023-2-24
Apologies,
Omega00= 3.5
Lambda355= 0.000355
The rest of the variables are themselves defined by other functions with yet more variables. The other functions are all working though.
Dyuman Joshi
Dyuman Joshi 2023-2-24
Rename your output variable name and run your code. As other functions are working properly, your code should work after the correction as well.

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采纳的回答

Jan
Jan 2023-2-24
移动：Jan 2023-2-24
Avoid using the name of the function as name of the output. This is confusing only.
Which is the failing line? In this line f355 is used as a variable, not as a function.
See this example:
sin(0.1) % Fine
sin = 15; % Now sin is a variable
sin(0.1) % Error: 0.1 is no valid index
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Theobold
Theobold 2023-2-24
Right I see, I ran a calculation earlier (since deleted) with f355= so I guess it's now assigned as a variable?
Thanks for the advice.

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