How to read a specially structured data file

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Jake
Jake 2023-2-27
编辑： Jake 2023-2-27
I have a *.5P file (file is an output from the software WAMIT, and can be read by Matlab and/or any text editor) that I want to read through Matlab. Since I cannot upload a *.5P file here in the forum, I changed it to a *.txt file and attached the sample file here.
Now, one line of this data file would include 19 columns (each separated by a tab or space). However, the specific structure of the output file "wraps" each data line to include only 15 columns, and the next 4 lines go into a new line. I'm trying the following code to read the data.
fid = fopen('test.5p');
C = cell2mat(textscan(fid, '%f %f %f %f %f %f %f %f %f %f %f %f %f %f %f %f %f %f %f'));
fclose(fid);
But this doesn't give me the structure I want, and instead, I get something similar to the following.
How can I read these wrapped lines to be one single line?
TIA!
** EDIT: I realized that I made a mistake with the question and the actual structure of the data file is a bit more complex than what I thought and had attached here. I posted a separate question detailing that.

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采纳的回答

Stephen23
Stephen23 2023-2-27
Ran in:
fid = fopen('test.txt','rt');
mat = fscanf(fid,'%f',[19,Inf]).';
fclose(fid);
display(mat)
mat = 300×19
-1.0000 1.0000 1.0000 0.0303 0 -0.0446 0 0.1337 0 -0.0016 0 0.0647 0 0.0461 0 -0.0446 0 0.0154 0 -1.0000 1.0000 2.0000 0.0318 0 -0.0505 0 0.1375 0 -0.0017 0 0.0679 0 0.0521 0 -0.0505 0 0.0190 0 -1.0000 1.0000 3.0000 0.0305 0 -0.0402 0 0.1327 0 -0.0013 0 0.0649 0 0.0418 0 -0.0402 0 0.0153 0 -1.0000 1.0000 4.0000 0.0301 0 -0.0314 0 0.1318 0 -0.0010 0 0.0634 0 0.0327 0 -0.0314 0 0.0115 0 -1.0000 1.0000 5.0000 0.0308 0 -0.0316 0 0.1329 0 -0.0009 0 0.0646 0 0.0330 0 -0.0316 0 0.0127 0 -1.0000 1.0000 6.0000 0.0316 0 -0.0416 0 0.1357 0 -0.0012 0 0.0672 0 0.0433 0 -0.0416 0 0.0173 0 -1.0000 1.0000 7.0000 0.0326 0 -0.0533 0 0.1392 0 -0.0017 0 0.0700 0 0.0550 0 -0.0533 0 0.0217 0 -1.0000 1.0000 8.0000 0.0324 0 -0.0444 0 0.1379 0 -0.0012 0 0.0692 0 0.0461 0 -0.0444 0 0.0196 0 -1.0000 1.0000 9.0000 0.0333 0 -0.0559 0 0.1413 0 -0.0016 0 0.0722 0 0.0575 0 -0.0559 0 0.0245 0 -1.0000 1.0000 10.0000 0.0349 0 -0.0650 0 0.1443 0 -0.0021 0 0.0741 0 0.0663 0 -0.0650 0 0.0277 0
  1 个评论
Jake
Jake 2023-2-27
Thank you @Stephen23, I accepted your answer because it aligned with what I had in mind. However, I'm so sorry that I had posted my question with a mistake. I posted a separate question detailing that. I'm sorry again.

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更多回答（2 个）

Jan
Jan 2023-2-27
编辑：Jan 2023-2-27
[fid, msg] = fopen('test.5p');
assert(fid > 0, '%s', msg);
C = fscanf(fid, '%g', inf); % Read all in one block
fclose(fid);
C = reshape(C, 19, []).'; % Reshape afterwards
  1 个评论
Jake
Jake 2023-2-27
Thank you @Jan! However, I'm so sorry that I had posted my question with a mistake. I was in a hurry, and overlooked the structure of my file, only to realize that the actual structure is a bit more complex than what I had stated. I posted a separate question detailing that. I'm sorry again.
Further, I had accepted Stephen23's answer since it aligned a bit more with what I had in mind :)

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Askic V
Askic V 2023-2-27
编辑：Askic V 2023-2-27
I would also like to suggest my naive and inefficient approach:
A = dlmread('testfile5p.txt');
nr_rows = size(A,1);
A2 = zeros(ceil(size(A,1)/2),19);
for i = 1:nr_rows-1
A2(i,:) = [A(i,:), A(i+1,1:4)];
end
B = A2(1:2:end,:);
The solution with using Inf plus transponse is really mind blowing. I would never expect that.

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