String in matrix for loop

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Maurizio 2011-10-25

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https://ww2.mathworks.cn/matlabcentral/answers/19293-string-in-matrix-for-loop

I have created the below for loop. The txt files are all composed by 16 elements, the first 8 are string and the seconde 8 are number and are separated by comma. At the moment I created a matrix with only the last 8 value. Is it possible also to create a matrix (no structure, no array) with also the first 8 string?

fileList = dir( '*.txt' );

for i = 1 : numel(fileList)

    nameFile{i} = fileList(i,1).name;
    NAME = char(nameFile(i) );
        fid = fopen( NAME );
        val = textscan( fid, '%s', 'delimiter', ',' );
        fclose( fid );
            if val{1,1}{5,1} == 'LIMA' | val{1,1}{6,1} == 'VOCI'
            % for jj =   1 : 7
            % VAL (i,jj)= char(val{1,1}{jj,1});
            % end
                for j = 8 : size( val{1,1},1 )
                    A(i, j) = str2num( val{1,1}{j,1} ); 
                   end
            end
end

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TAB 2011-10-25

(no structure, no array).

What about cell array ?

Maurizio 2011-10-25

Tabrez the values on the *.txt are for example:

A6,ANB,AUG23,204704,OMDC,VOCI,0404,0790,0468,05330,01420,14800,08550,0780

and I have n*file txt.

I need to create a for loop that each collect this 14 values and create a matrix with 14 columns and n rows.

Thanks a lot

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回答（1 个）

Daniel Shub 2011-10-25

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https://ww2.mathworks.cn/matlabcentral/answers/19293-string-in-matrix-for-loop#answer_25677

It really depends on what data type you are willing to allow. You say no structure and no array. MATLAB only deals with arrays; scalars are arrays with a length of 1. It seems like you also do not want cell arrays, since your data from textscan is a cell array.