How to write the equation in matlab I= A A* T² exp (qob/kT) exp (q(V - Rs I /kT)) (exp (-1/n) ? Why is the curve not shown in the drawing?

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Han 2023-3-19

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评论： Dyuman Joshi 2023-3-20

clear; close all; clc; n=5.2; %Ideality factor A =8.16; %Richardson constant q = 1.602e-19; % electron charge K = 1.380e-23; %Boltzmann constant T =140; % Absolute temperature phi_b = 0.43; %Barrier Height V =(0:0.1:2); Rs=7.74e9; %Resistance a=2.8e-5; %the effective area I1=1.5; I =A*a* (T.* T).* exp((-q.* phi_b)/(K* T).*exp((q.* V) ./ ( K* T))) .*exp((-q .*I1.*Rs) ./ (K* T).*(-1/n)); %corrected the paranthesis plot(V,I)

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Han 2023-3-19

Yes, the formula is correct

Dyuman Joshi 2023-3-20

If the formula is correct, then so is the output and the plot from the code in my comment above.

The formula in above code is according to the formula in the title.

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回答（2 个）

Torsten 2023-3-19

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在 MATLAB Online 中打开

Maybe you mean

I = A*a*T^2*exp(q*phi_b/(K*T))*exp(q*(V-I1*Rs/(K*T)))*exp(-1/n)

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John D'Errico 2023-3-19

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在 MATLAB Online 中打开

n=5.2;
%Ideality factor
A =8.16;
%Richardson constant
q = 1.602e-19;
% electron charge
K = 1.380e-23;
%Boltzmann constant
T =140;
% Absolute temperature
phi_b = 0.43;
%Barrier Height
V =(0:0.1:2);
Rs=7.74e9;
%Resistance
a=2.8e-5;
%the effective area
I1=1.5;
I =A*a* (T.* T).* exp((-q.* phi_b)/(K* T).*exp((q.* V) ./ ( K* T))) .*exp((-q .*I1.*Rs) ./ (K* T).*(-1/n));
%corrected the paranthesis
I
I = 1×21
   Inf   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN

Before you plot it, why not look at the numbers you generated?

Remember that MATLAB uses DOUBLE PRECISION floating point arithmetic.

I would strongly suggest you compute the log of that expression. No, don't compute the variable I, then try to take the log. Take the log, by adding the logs of each individual term. Don''t even try to compute those exponentials. Remember that log(exp(x))=x.