How can i display this user defined matrix made with a loop

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Kaden
Kaden 2023-4-17
回答： Walter Roberson 2023-4-18
I used a loop to create a user defined matrix and i want to display in column form not row form. I can not get the code to fprintf in column form, any help would be greatly appreciated.
n = input('Enter your number of rows: ');
m = input('Enter your number of columns: ');
fprintf('Select a function:\n');
fprintf('1) Add\n');
fprintf('2) Subtract\n');
fprintf('3) Multiply\n');
fprintf('4) Divide\n');
fun_choice = input('Enter your choice (1:4): ');
% Calculation section:
matrix = zeros(n, m);
for k = 1:n
for h = 1:m
if fun_choice == 1
matrix(k, h) = k + h;
elseif fun_choice == 2
matrix(k, h) = k - h;
elseif fun_choice == 3
matrix(k, h) = k * h;
elseif fun_choice == 4
matrix(k, h) = k / h;
end
end
end
  2 个评论
Dyuman Joshi
Dyuman Joshi 2023-4-18
Ran in:
Say n=4, m=5 and fun_choice is 1. What is the output you want?
n=4;m=5;
matrix = zeros(n, m);
fun_choice = 1;
for k = 1:n
for h = 1:m
if fun_choice == 1
matrix(k, h) = k + h;
elseif fun_choice == 2
matrix(k, h) = k - h;
elseif fun_choice == 3
matrix(k, h) = k * h;
elseif fun_choice == 4
matrix(k, h) = k / h;
end
end
end
matrix
matrix = 4×5
2 3 4 5 6 3 4 5 6 7 4 5 6 7 8 5 6 7 8 9

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回答（2 个）

KSSV
KSSV 2023-4-18
n=4;m=5;
matrix = zeros(n, m);
fun_choice = 1;
for k = 1:n
for h = 1:m
if fun_choice == 1
matrix(k, h) = k + h;
elseif fun_choice == 2
matrix(k, h) = k - h;
elseif fun_choice == 3
matrix(k, h) = k * h;
elseif fun_choice == 4
matrix(k, h) = k / h;
end
end
end
fprintf('%f\n',matrix(:)) % print as column using fprintf
matrix(:)
fprintf('%f %f %f %f\n',matrix) % print like matrix using fprintf
matrix
Walter Roberson
Walter Roberson 2023-4-18
Ran in:
My suspicion is that you have a situation something like
M = magic(4)
M = 4×4
16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1
fprintf('%d %d %d %d\n', M)
16 5 9 4 2 11 7 14 3 10 6 15 13 8 12 1
and you are noticing that the output rows such as 16 5 9 4 do not correspond to the rows of the data, like 16 2 3 13
If so, there are two ways to proceed:
First you can do
fprintf('%d %d %d %d\n', M.')
16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1
The number of %d should be the same as the number of columns of data.
Or, you can use
compose("%d %d %d %d", M)
ans = 4×1 string array
"16 2 3 13" "5 11 10 8" "9 7 6 12" "4 14 15 1"
Or you can combine
fprintf('%s\n', compose("%d %d %d %d", M)) %format is used once per entry in the string array
16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1
or
fprintf('%s\n', join(compose("%d %d %d %d", M),newline)) %format is used once
16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1

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