extract row from a cell
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Hi! I generated a cell similar to this one:
a = {'home'};
b = {'ball' , 'cake' , 'ice'};
c = {'car','moto'};
d = {'money','supercar','toys'};
e = cell(4,0);
e(1,1:numel(a)) = a;
e(2,1:numel(b)) = b;
e(3,1:numel(c)) = c;
e(4,1:numel(d)) = d
I want to extract from cell "e" the first row consisting of three values.
In the case above, the second row of cell "e" consists of three values, one per column. I want to extract this second row.
采纳的回答
a = {'home'};
b = {'ball' , 'cake' , 'ice'};
c = {'car','moto'};
d = {'money','supercar','toys'};
e = cell(4,0);
e(1,1:numel(a)) = a;
e(2,1:numel(b)) = b;
e(3,1:numel(c)) = c;
e(4,1:numel(d)) = d;
% construct a logical matrix the same size as e saying whether each
% corresponding cell of e is non-empty:
e_nonempty = ~cellfun(@isempty,e)
% find the first row of e that has three non-empty cells:
row = find(sum(e_nonempty,2) == 3,1)
% extract that row of e:
result = e(row,:)
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