Rename folders using folder names saved in cells

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Alberto Acri 2023-6-18

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1984834-rename-folders-using-folder-names-saved-in-cells

评论： Steven Lord 2023-6-19

采纳的回答： the cyclist

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I have a folder 'A' inside which I have numbered folders. I saved the folder numbers inside a cell:

cell_numbers = {2;10;22;48};

I want to rename those folders with the names contained in this cell:

cell = {'parameter_1';'parameter_2';'parameter_3';'parameter_4'};

So I want that:

- the folder '2' will be called 'parameter_1'

- the folder '10' will be called 'parameter_2'

- the folder '22' will be called 'parameter_3'

- the folder '48' will be called 'parameter_4'

采纳的回答

the cyclist 2023-6-18

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1984834-rename-folders-using-folder-names-saved-in-cells#answer_1258229

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Here is one way:

cell_numbers = {2;10;22;48};
cell = {'parameter_1';'parameter_2';'parameter_3';'parameter_4'}; % <---- You should rename this variable, because "cell" is a MATLAB function name
for nc = 1:numel(cell_numbers)
    movefile(sprintf("%d",cell_numbers{nc}),cell{nc})
end

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Alberto Acri 2023-6-19

Thank you @the cyclist, it works. It was easier than expected!

Steven Lord 2023-6-19

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You've got a mismatch somewhere between numbers and characters. What are characters 52 and 53?

char(52)
ans = '4'
char(53)
ans = '5'

What are the names of your first two files?

Looking at the third file, characters 49 and 54 are '1' and '6'.

char([49 54])
ans = '16'

I'm guessing somewhere you tried assigning text data into a numeric array using subscripted indexing.

x = 1:10 % numeric array
x = 1×10
     1     2     3     4     5     6     7     8     9    10
x(5) = '5' % x(5) becomes 53 because char(53) is '5'
x = 1×10
     1     2     3     4    53     6     7     8     9    10

I recommend using a string array instead, as assigning numbers into a string array or vice versa converts them the way you probably expect (5 becomes "5" and vice versa rather than '5' becoming 53 and vice versa.)

x(8) = "64" % Assign string into numeric array
x = 1×10
     1     2     3     4    53     6     7    64     9    10
s = string(x)
s = 1×10 string array
    "1"    "2"    "3"    "4"    "53"    "6"    "7"    "64"    "9"    "10"
s(2) = 999 % Assign number into string array
s = 1×10 string array
    "1"    "999"    "3"    "4"    "53"    "6"    "7"    "64"    "9"    "10"