The function of generating HDL code has an error with the names of blocks in the same Subsystem

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Ho 2023-7-14

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1995888-the-function-of-generating-hdl-code-has-an-error-with-the-names-of-blocks-in-the-same-subsystem

评论： Ho 2023-7-16

Anyone know how to fix this please help me.

I'm currently working on this example: https://www.mathworks.com/help/wireless-hdl/ug/hdlofdmtransmitter.html

and in the subsystem "OFDM Transmitter" will contain the subsystem "whdlOFDMTx Model". When I do generate HDL code, the name of the subsystem "whdlOFDMTx Model" is "whdlOFDMTx_whdlOFDMTx" but in the HDL code of the top file its name is "whdlOFDMTx"; Similar to the blocks "frame_controller_and_input_sampler", "frame_generator", "multiplexer", "Discrete_FIr_filter", its name in the command line called "Whdlofdmtx_Frame_controller_and_input_sampler", "whdlOFDMTx_Frame Fdmtx_multyxer "," whdlOFDMTx_DISCRETE_FIR_FILTER "

This is in the code that calls the "whdlOFDMTx" subsystem block in the TOP vhdl

And here is the declared name of the "whdlOFDMTx" subsystem in the file vhdl

Therefore, it cannot recognize sub-blocks

Someone know please help me

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Ho 2023-7-14

Does anyone know another way to fix this error? help me please

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Answer 1

Bharath Venkataraman 2023-7-14

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There is a configuration statement in line 101 which maps whdlOFDMTx to use the entity work_whdlOFDMTx.whdlOFDMTx_whdlOFDMTx(rtl). This tells the tool to map whdlOFDMTx to whdlOFDMTx_whdlOFDMTx.

If that is not working, you can rename all uses of whdlOFDMTx to whdlOFDMTx_whdlOFDMTx.

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Answer 2

Kiran Kintali 2023-7-15

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此回答的直接链接

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编辑：Kiran Kintali 2023-7-15

在 MATLAB Online 中打开

" ... in the subsystem "OFDM Transmitter" will contain the subsystem "whdlOFDMTx Model". When I do generate HDL code, the name of the subsystem "whdlOFDMTx Model" is "whdlOFDMTx_whdlOFDMTx" ..."

If you are looking to control the default name of the file generated from a model reference block you can set the reference block parameter to empty (to remove the modelname prefix) or use your desired prefix string.