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Error in parfor (First argument must be scalar.)

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Bhooshan
Bhooshan 2023-10-16
评论： Sam Marshalik 2023-10-16
I am getting error in parfor as
First argument must be scalar.
in my code i use
parpool(4)
parfor i=1:l
where l is a scalar
when i use just for i=1:l and disbles parpool
the program runs just fine
what i am missing here?
  1 个评论
Bhooshan
Bhooshan 2023-10-16
编辑：Bhooshan 2023-10-16
Error using sym/factor (line 51)
First argument must be scalar
Error in mtp (line 17)
parfor i=1:l
is the exact error

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回答（1 个）

Walter Roberson
Walter Roberson 2023-10-16
The error is not on the parfor line. The error is in the call to factor() that is somewhere in your parfor loop

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