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How do I find all odd numbers between 1 and 60 but are divisible by 5?

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Samariah 2023-10-21

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编辑： Torsten 2023-10-21

How do I find all odd numbers between 1 and 60 but are divisible by 5 using the for loop?

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Dyuman Joshi 2023-10-21

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Please show what you have attempted yet.

Samariah 2023-10-21

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在 MATLAB Online 中打开

Ran in:

for i = 1:2:60
  disp(i)
  end 
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Dyuman Joshi 2023-10-21

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That's a good start on the for loop, but you are not testing for divisilibility with 5.

You should include that in your code.

Samariah 2023-10-21

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编辑：Samariah 2023-10-21

That's the part I got stuck on. How do I do that? Would it be possible if I can get an example?

Dyuman Joshi 2023-10-21

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How would you test for divisibility by 5 via pen and paper?

Stephen23 2023-10-21

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"That's the part I got stuck on. How do I do that?"

Have a think about what it means to for a value to be "divisible by five": (hint: what is the remainder?)

Samariah 2023-10-21

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Well I know the numbers divisble by 5 betwen 1-60 are 5,15,25, and 35. I tried putting disp(i/5) but that didn't work.

Dyuman Joshi 2023-10-21

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"I know the numbers divisble by 5 ..."

How do you know that? What criteria did you apply to know that?

Take a look at the hint Stephen23 has provided above.

Samariah 2023-10-21

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Well I know that the last number has to end with 5 in order for it to be divisible by 5.

Torsten 2023-10-21

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Odd means: when divided by 2, it gives remainder 1.

Divisible by 5 means: when divided by 5, it gives remainder 0.

Now think about how to use "mod":

https://uk.mathworks.com/help/matlab/ref/mod.html

Samariah 2023-10-21

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mod(60, 5) this gave me 0 but how to I incorporate this into my for loop?

Torsten 2023-10-21

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编辑：Torsten 2023-10-21

在 MATLAB Online 中打开

This is almost a solution. More hints are not possible.

for i = 1:60
  if mod(...) == 1 && mod(...) == 0
    disp(i)
  end
end

or shorter

X = 1:60;
X = X(mod(...) == 1 & mod(...) == 0)

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回答（1 个）

Walter Roberson 2023-10-21

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在 MATLAB Online 中打开

Ran in:

hint:

for i = 1 : 60
    r7 = remainder7(i);
    if r7 == 0; disp(i); end
end
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function v = remainder7(v)
  while v >= 7
      v = v - 7;
  end
end