how to check if numbers in the vector is within range of 1:10

190 次查看（过去 30 天）
GOENG
GOENG 2015-4-16
编辑： Jan 2015-4-16
while length(x) == 6
if x < -36 && x > 47
If there was an input and I had to check if the values of the array is within the elements of 1:10, how can i do it?
I though just checking if the input of array was bigger or small than the limited number it works but it didn't.
I'm assuming you have to check either all at once or one by one.
could someone help me?
Thank you in advance =]

请先登录，再回答此问题。

回答（2 个）

Thorsten
Thorsten 2015-4-16
all(x >= 1 & x <= 10)
  2 个评论
GOENG
GOENG 2015-4-16
I got an error for this
if all(inPut > -36 && inPut < 46)
disp('Do it again, within -36 to 46, and size of 1 by 6: ');
inPut = input('Please put a number within -36 to 46: ');
else
error message: Operands to the and && operators must be convertible to logical scalar values.
i put in the vector of inPut = [55 55 55 55 55 44] so one of the number is within range and the other 5 isn't to check.
James Tursa
James Tursa 2015-4-16
Thorsten used a single &, and you used a double &&. The single & is element-wise operator and the double && is intended for scalar operands only. Use a single &.

请先登录，再进行评论。

Jan
Jan 2015-4-16
编辑：Jan 2015-4-16
If the inputs are large, the creation of the temporary arrays consumes a lot of time. Then this MEX function is more efficient: FEX: anyExceed :
if anyExceed(x, 1, 10)
This avoids creating the temporary arrays t1 = x >=1 , t2 = x<=10 and t1&t2 and the code stops at the first matching element.
  1 个评论
GOENG
GOENG 2015-4-16
unfortunately it has to be something built in only. No external files but thanks for the link, that really does make it simpler.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by