how do I find the x-axis value from my yline intercept on my acceleration curve

2 次查看（过去 30 天）

Sam 2023-11-1

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2041666-how-do-i-find-the-x-axis-value-from-my-yline-intercept-on-my-acceleration-curve

评论： Dyuman Joshi 2023-11-3

I have an acceleration curve and i need to find the 0-60mph (0-26.8224m/s) Stuck on how to get there, currently only have a yline that shows where 26.8224m/s along the y-axis. Please help! Here's my code and a picture of the graph:

figure(6)
P1 = plot(tout,yout(:,1));
xlabel('Time (s)')
ylabel('Velocity (m/s)')
grid on
set(P1,'linewidth',2)
title('Acceleration Curve')
yline(26.8224)

2 个评论
显示无隐藏无

Dyuman Joshi 2023-11-2

I believe there's a typo in the problem statment. It should be 0-60m/s

Dyuman Joshi 2023-11-2

@Sam, what is the relation between velocity and time? Do you have an expression/equation?

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Voss 2023-11-1

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2041666-how-do-i-find-the-x-axis-value-from-my-yline-intercept-on-my-acceleration-curve#answer_1344961

在 MATLAB Online 中打开

% some data:

tout = (0:60).';

yout = 10*log(tout+1);

y_val = 26.8224;

% your plot:

P1 = plot(tout,yout(:,1),'linewidth',2);

xlabel('Time (s)')

ylabel('Velocity (m/s)')

grid on

title('Acceleration Curve')

yline(y_val)

% find the t value where y is y_val:

t0 = interp1(yout(:,1),tout,y_val)

t0 = 13.6259

% plot a vertical red line to that point on the curve:

hold on

plot([t0,t0],[0,y_val],'--r')

4 个评论
显示 2更早的评论隐藏 2更早的评论

Voss 2023-11-3

Linear interpolation gives a point on the curve MATLAB plotted. If there's a non-linear function underlying that curve, use an interpolation method suitable to that function in your judgment.