Trying to Solve system of 2 Equations "Unable to find explicit solution" Code In Description

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Code pasted below, thanks in advance:
clear all;
close all;
clc;
% Solve System of Equations
syms a1 a2 a3 r_1 r_2 alpha E
a3 = (alpha*E)/(8*pi);
[sol_a1, sol_a2] = solve(2*a3*log(r_1) + (a1/(r_1)^2) + a3 + 2*a2 == 0,...
2*a3*log(r_2) + (a1/(r_2)^2) + a3 + 2*a2 == 0);
Warning: Unable to find explicit solution. For options, see help.

采纳的回答

Walter Roberson
Walter Roberson 2023-11-4
syms a1 a2 a3 r_1 r_2 alpha E
a3 = (alpha*E)/(8*pi);
eqn = [2*a3*log(r_1) + (a1/(r_1)^2) + a3 + 2*a2 == 0,...
2*a3*log(r_2) + (a1/(r_2)^2) + a3 + 2*a2 == 0];
partial_1 = solve(eqn(1), a1)
partial_1 = 
eqn2 = subs(eqn(2:end), a1, partial_1)
eqn2 = 
partial_2 = solve(eqn2(1), a2)
partial_2 = 
sol_a2 = partial_2
sol_a2 = 
sol_a1 = subs(partial_1, a2, sol_a2)
sol_a1 = 
%cross-check
subs(eqn, {a1, a2}, {sol_a1, sol_a2})
ans = 
isAlways(ans)
ans = 1×2 logical array
1 1
%or... more directly...
syms a1 a2 a3 r_1 r_2 alpha E
a3 = (alpha*E)/(8*pi);
[sol_a1, sol_a2] = solve(2*a3*log(r_1) + (a1/(r_1)^2) + a3 + 2*a2 == 0,...
2*a3*log(r_2) + (a1/(r_2)^2) + a3 + 2*a2 == 0, [a1, a2])
sol_a1 = 
sol_a2 = 
simplify(sol_a1)
ans = 
simplify(sol_a2)
ans = 
  4 个评论
Walter Roberson
Walter Roberson 2023-11-6
When you have a sym() or symfun() or symmatrix() expression, then that sort of formatting happens automatically if you are using LiveScript or MATLAB Online or MATLAB Answers. It does not happen if you are using the traditional command window (and there is no way to turn it on for the command window)

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更多回答(1 个)

Sulaymon Eshkabilov
编辑:Sulaymon Eshkabilov 2023-11-4
Note that you have six unknowns (a1, a2, r_1, r_2, alpha, E) an two equations. It is possible to get two solution type expressions using IgnoreAnalyticalConstraints option, e.g.:
syms a1 a2 r_1 r_2 alpha E
a3 = (alpha*E)/(8*pi);
SOLUTION = solve(2*a3*log(r_1) + (a1/(r_1)^2) + a3 + 2*a2 == 0,...
2*a3*log(r_2) + (a1/(r_2)^2) + a3 + 2*a2 == 0, "IgnoreAnalyticConstraints",true)
SOLUTION = struct with fields:
r_1: exp(-((E*alpha)/2 + 8*pi*a2)/(E*alpha))*exp(wrightOmega(log(-(8*pi*a1)/(E*alpha)) + (E*alpha + 16*pi*a2)/(E*alpha))/2) r_2: exp(-((E*alpha)/2 + 8*pi*a2)/(E*alpha))*exp(wrightOmega(log(-(8*pi*a1)/(E*alpha)) + (E*alpha + 16*pi*a2)/(E*alpha))/2)
r_1 = SOLUTION.r_1
r_1 = 
r_2 = SOLUTION.r_2
r_2 = 
a3 = (alpha*E)/(8*pi)
a3 = 

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