Changing function handle within a MATLAB Function block in Simulink (Coder error)

Question

James Floyd 2023-11-7

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2044302-changing-function-handle-within-a-matlab-function-block-in-simulink-coder-error

回答： Sakshi Sharma 2023-11-8

I have a function block in Simulink that takes in an input and time and then, based on the input, chooses from a switch-case stack which function to use. The functions being chosen from are named exactly the same but held in 2 different package folders under one larger package folder. The chosen function is then evaluated and the output is returned.

The code inside the MATLAB Function Block looks like this:

function y = calc(t, option)
y = 0;
funcs = cell(2, 1);
funcs{1} = @FunctionPaths.FunctionPath1.dummy; % "dummy" is the name of the function within the FunctionPath1 package
funcs{2} = @FunctionPaths.FunctionPath2.dummy;
switch option
    case 1
        func = funcs{1};
    case 2
        func = funcs{2};
    otherwise
        error('Choice of "option" outside of acceptable range.')
end
y(:) = func(t);
end

The issue comes from the "funcs{2}" line: Type mismatch: MATLAB Coder cannot determine the equivalence of function handles FunctionPaths.FunctionPath1.dummy versus FunctionPaths.FunctionPath2.dummy.

How can I fix this issue?

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Answer 1

Sakshi Sharma 2023-11-8

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2044302-changing-function-handle-within-a-matlab-function-block-in-simulink-coder-error#answer_1348702

Variable which holds the function handle has to be compile time constant. In this case the function handle variable is 'func'. For this to be constant the function argument 'option' has to be passed as coder.Constant.