清空筛选条件
清空筛选条件

Illegal use of reserved keyword "elseif" keep showing up?

5 次查看（过去 30 天）
mohammad
mohammad 2023-11-9
评论： mohammad 2023-11-9
function isortvector
A = [9 -7 8 4 -3 7]
inp = input("enter 0 for ascendig && 1 for decending");
ascending = [];
descendig = [];
if inp == '0'
for i = 1:6
x = A(1);
for j=1:length(A)
if A(j) < x
x=A(j);
end
end
ascending(end+1)=x; A(A==x)=[];
end
disp("Ascending:"); disp(ascending)
end
elseif inp =='1'
for i = 1:6
x=A(1);
for j=1:length(A)
if A(j) > x
x = A(j);
end
descending(end+1) = x; A(A==x)=[];
end
disp("Descending:");
disp(descendig)
disp("uncorect input:")
disp(A)
end
end
[SL: formatted code as code]
  1 个评论
Stephen23
Stephen23 2023-11-9
编辑：Stephen23 2023-11-9
Note that as you have called it INPUT will return numeric values. If you expect characters (as you show use with IF and ELSEIF) then you will need to use the 's' option:
inp = input("enter 0 for ascendig && 1 for decending","s");
% ^^^
You also have to fix the names of some variables.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Stephen23
Stephen23 2023-11-9
编辑：Stephen23 2023-11-9
If you align your code consistently then the problem is very clear:
if inp == '0'
..
end % <- delete this
elseif inp =='1'
..
end
Tip: to align code automatically select all of your code and press ctrl+i.

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 File Operations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by