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How do I avoid the mistake?

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Alisa-Oleksandra Kotliarova
评论： Alisa-Oleksandra Kotliarova 2023-12-13
I have the following function:
function [x,y,k] = Hord(fun,a,b,tolx,toly)
ya=feval(fun,a);
k=0;
while 1
k=k+1;
x=(a*fun(b)-b*fun(a))./(fun(b)-fun(a));
y=feval(fun,x);
if(x(k)-x(k-1)<=tolx)&(abs(y)<=toly), break, end
if y*ya>0; a=x; ya=y;
else b=x;
end
end
Then my code is:
clc, clear all, close all, format short
x1=linspace(-pi/2,pi/2);%Заданий інтервал значень;
y1=cos(x1+0.3)-x1.^2;%Функція 1;
figure(1), plot(x1,y1,[-pi/2,pi/2], [0,0]),grid on, hold on%Графік;
f1=(@(x1) cos(x1+0.3)-x1.^2);%Анонімне задання функції 1;
format long
[X1,Y1] = Hord(f1, 0, pi/2, 1e-3, eps);%Перший додатний корінь;
X1,Y1%Виведення кореня;
plot(X1,Y1,'o','r--')%На графіку;
It should output the graph with a root, however, it only gives:
Array indices must be positive integers or logical values.
Error in Hord (line 9)
if(x(k)-x(k-1)<=tolx)&(abs(y)<=toly), break, end
Error in Lab7_var2 (line 36)
[X1,Y1] = Hord(f1, 0, pi/2, 1e-3, eps);%Перший додатний корінь;
How can I correct it?

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采纳的回答

Torsten
Torsten 2023-12-11
编辑：Torsten 2023-12-11
x in your code is a scalar, not a vector. Thus something like x(k) does not exist.
You could work with xold and x where xold would be the x-value of the previous iteration.

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Image Analyst
Image Analyst 2023-12-13

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