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100 permutation

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Niki 2011-11-9

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I have the following matrix

x =

   2     3     4     5
   7     8     9    10
  12    13    14    15
  17    18    19    20

I would like to have 100 different permutation and in each I change randomly one variable of each row with others like this

1 7 13 4 5 
then 
11 5 4 19 2
and so on

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Jan 2011-11-9

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What have you tried so far and which specific problem occurred?

Image Analyst 2011-11-9

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In your first example, which row was that? Was it row 1? If so, it looks like 2 numbers got changed, not 1. And the next row does not look like it's only one number different than row 2.

Niki 2011-11-9

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yes, I need the combination , it does not matter for me how many changes

Fangjun Jiang 2011-11-9

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Then you need to clarify your question. You said "change randomly one variable of each row", which does not match your example.

Image Analyst 2011-11-9

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And I consider "x" the variable. The numbers in the rows of x are simply "numbers" or "elements of x" not variables in themselves. At least that's how I think of it. I still have no idea which row got changed (in ANY way at all) to form "11 5 4 19 2"

Niki 2011-11-9

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it does not matter, for example at first it can starts with all possible changes with the first row , for example

1 7 13 19 20

1 11 3 4 5

1 6 14 15 20

and ....

then start with second one

however it does not matter which row , just from the first until the end

Niki 2011-11-9

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You can take a look at this

http://www.mathworks.com/matlabcentral/answers/20551-combination

Daniel Shub 2011-11-9

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In the end are you going to want the solution to be able to extend to a much larger matrix. If this is a simplification, it would help to let us know in advance. Also, like IA, I have no idea what is changing and how in your example.

Dr. Seis 2011-11-9

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Your examples are confusing. Let's say the resulting combination is the general form:

A B C D E

What range of numbers can A, B, C, D, and E be?

At first I thought that:

A can equal 1, 6, 11, or 16

B can equal 2, 7, 12, or 17

C can equal 3, 8, 13, or 18

D can equal 4, 9, 14, or 19

E can equal 5, 10, 15, or 20

But after your first example, that logic breaks down.

Niki 2011-11-9

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yes

it should be the same dimension,

for example if you have 5 variable in each row

then the created row should be included of 5 variables from each row

Niki 2011-11-9

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please take a look at this ,

http://www.mathworks.com/matlabcentral/answers/20551-combination

I think andri is doing well, but I want to put a limitation for example just 100 permutation

and on the other hand, I want to perform it not only on one raw but also for others

Titus Edelhofer 2011-11-9

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Hi Mohammad,

a suggestion: for 6 hours now people try to answer your question (and fail) just because nobody get's from your question a clear impression about what you want to do exactly. Perhaps it's time to elaborate on what you have and what exactly you want to get together with a meaningful (!) example ...??

Titus

Niki 2011-11-9

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Dear Titus

it is really clear Let say we have a matrix

x =

1 2 3 4 5

6 7 8 9 10

11 12 13 14 15

16 17 18 19 20

then I want to get 100 permutation by changing the variables of each row

1 2 3 4 5

1 7 8 9 10

1 12 13 14 15

1 17 18 19 20

6 2 3 4 5

6 7 8 9 10

6 12 13 14 15

6 17 18 19 20

11 2 3 4 5

11 7 8 9 10

11 12 13 14 15

11 17 18 19 20

16 2 3 4 5

16 7 8 9 10

16 12 13 14 15

16 17 18 19 20

but I want to put a limitation , for example only 100 or more or less

and also the matrix that I put as an example was included of 5 variables but I want to do that for a matrix with more or less dimention

Image Analyst 2011-11-9

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It's getting clearer. The above seems clear but I'm not sure where [11 5 4 19 2] comes from in your first post. That is not in your list just now.

Sven 2011-11-10

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Mohommad, have I answered your question on the original thread?

http://www.mathworks.com/matlabcentral/answers/20551-combination

Just set solutionLimit = 100, and it seems to solve this exact same question.

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回答（1 个）

Dr. Seis 2011-11-9

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Stab in the dark:

sizeX = [4,5];
permlimit = 100;
X = reshape(1:prod(sizeX),fliplr(sizeX))';
Y = zeros([permlimit, sizeX(2)]);
for ii = 1 : permlimit
  for jj = 1 : sizeX(2)
      Y(ii,jj) = X(randi(sizeX(1)),jj);
  end
end
disp(Y)