100 permutation

2011 11 9
1 个回答
2 次查看（30 天）

0 个投票

I have the following matrix
x =
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
I would like to have 100 different permutation and in each I change randomly one variable of each row with others like this
1 7 13 4 5
then
11 5 4 19 2
and so on

15 个评论
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Jan
Jan 2011-11-9
What have you tried so far and which specific problem occurred?
Image Analyst
Image Analyst 2011-11-9
In your first example, which row was that? Was it row 1? If so, it looks like 2 numbers got changed, not 1. And the next row does not look like it's only one number different than row 2.
Niki
Niki 2011-11-9
yes, I need the combination , it does not matter for me how many changes
Fangjun Jiang
Fangjun Jiang 2011-11-9
Then you need to clarify your question. You said "change randomly one variable of each row", which does not match your example.
Image Analyst
Image Analyst 2011-11-9
And I consider "x" the variable. The numbers in the rows of x are simply "numbers" or "elements of x" not variables in themselves. At least that's how I think of it. I still have no idea which row got changed (in ANY way at all) to form "11 5 4 19 2"
Niki
Niki 2011-11-9
it does not matter, for example at first it can starts with all possible changes with the first row , for example
1 7 13 19 20
1 11 3 4 5
1 6 14 15 20
and ....
then start with second one
however it does not matter which row , just from the first until the end
Niki
Niki 2011-11-9
You can take a look at this
http://www.mathworks.com/matlabcentral/answers/20551-combination
Daniel Shub
Daniel Shub 2011-11-9
In the end are you going to want the solution to be able to extend to a much larger matrix. If this is a simplification, it would help to let us know in advance. Also, like IA, I have no idea what is changing and how in your example.
Dr. Seis
Dr. Seis 2011-11-9
Your examples are confusing. Let's say the resulting combination is the general form:
A B C D E
What range of numbers can A, B, C, D, and E be?
At first I thought that:
A can equal 1, 6, 11, or 16
B can equal 2, 7, 12, or 17
C can equal 3, 8, 13, or 18
D can equal 4, 9, 14, or 19
E can equal 5, 10, 15, or 20
But after your first example, that logic breaks down.
Niki
Niki 2011-11-9
yes
it should be the same dimension,
for example if you have 5 variable in each row
then the created row should be included of 5 variables from each row
Niki
Niki 2011-11-9
please take a look at this ,
http://www.mathworks.com/matlabcentral/answers/20551-combination
I think andri is doing well, but I want to put a limitation for example just 100 permutation
and on the other hand, I want to perform it not only on one raw but also for others
Titus Edelhofer
Titus Edelhofer 2011-11-9
Hi Mohammad,
a suggestion: for 6 hours now people try to answer your question (and fail) just because nobody get's from your question a clear impression about what you want to do exactly. Perhaps it's time to elaborate on what you have and what exactly you want to get together with a meaningful (!) example ...??
Titus
Niki
Niki 2011-11-9
Dear Titus
it is really clear Let say we have a matrix
x =
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
then I want to get 100 permutation by changing the variables of each row
like
1 2 3 4 5
1 7 8 9 10
1 12 13 14 15
1 17 18 19 20
6 2 3 4 5
6 7 8 9 10
6 12 13 14 15
6 17 18 19 20
11 2 3 4 5
11 7 8 9 10
11 12 13 14 15
11 17 18 19 20
16 2 3 4 5
16 7 8 9 10
16 12 13 14 15
16 17 18 19 20
but I want to put a limitation , for example only 100 or more or less
and also the matrix that I put as an example was included of 5 variables but I want to do that for a matrix with more or less dimention
Image Analyst
Image Analyst 2011-11-9
It's getting clearer. The above seems clear but I'm not sure where [11 5 4 19 2] comes from in your first post. That is not in your list just now.
Sven
Sven 2011-11-10
Mohommad, have I answered your question on the original thread?
http://www.mathworks.com/matlabcentral/answers/20551-combination
Just set solutionLimit = 100, and it seems to solve this exact same question.

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回答（1 个）

Dr. Seis
Dr. Seis 2011-11-9

0 个投票

Stab in the dark:
sizeX = [4,5];
permlimit = 100;
X = reshape(1:prod(sizeX),fliplr(sizeX))';
Y = zeros([permlimit, sizeX(2)]);
for ii = 1 : permlimit
for jj = 1 : sizeX(2)
Y(ii,jj) = X(randi(sizeX(1)),jj);
end
end
disp(Y)

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Niki
Niki
2011-11-9

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