How to do a Biquad (SOS) filtering

12 次查看(过去 30 天)
I have the following filters which I want to implement with cascade of multiple second-order sections (SOS).
%% Filter_1
h = fdesign.bandpass('N,F3dB1,F3dB2', 10, 100e3, 120e3, 400e3);
Hd = design(h, 'butter');
Hd = convert(Hd, 'df2sos');
%% Filter_2
[be,ae] = ellip(4,1,40,0.2);
f = 0:0.001:0.2;
g = grpdelay(be,ae,f,2);
a = max(g)-g;
[num,den]=iirgrpdelay(8, f, [0 0.2], a);
[sos,g] = tf2sos(num,den);
So there are 9 SOS filters (e.g., 5 from the Filter_1 and 4 from the Filter_2) and I want to cascade all these. Is there a way to filter these nine filters all together? Or am I supposed to filter Filter 1 first and then apply Filter 2 later? Any example for each case?

采纳的回答

Paul
Paul 2024-1-24
编辑:Paul 2024-1-24
Hi Jay,
I think it works like this if you want to cascade the filters together into a single, sos filter.
%% Filter_1
h = fdesign.bandpass('N,F3dB1,F3dB2', 10, 100e3, 120e3, 400e3);
Hd = design(h, 'butter');
Hd = convert(Hd, 'df2sos');
sos1 = Hd.sosMatrix;
g1 = prod(Hd.ScaleValues)
g1 = 5.9796e-05
%% Filter_2
[be,ae] = ellip(4,1,40,0.2);
f = 0:0.001:0.2;
g = grpdelay(be,ae,f,2);
a = max(g)-g;
[num,den]=iirgrpdelay(8, f, [0 0.2], a);
[sos2,g2] = tf2sos(num,den);
%% Filter_3 is the combined filter
sos3 = [sos1;sos2];
g3 = g1*g2
g3 = 8.7612e-06
Frequency response Hd compared to sos1
[hd,wd] = freqz(Hd);
h1 = freqz(sos1,wd); h1 = h1*g1;
figure
subplot(211);plot(wd,db(abs([hd h1])));grid
subplot(212);plot(wd,180/pi*angle([hd h1]));grid
Frequency response of sos2 and sos3
h2 = freqz(sos2,wd); h2 = h2*g2;
h3 = freqz(sos3,wd); h3 = h3*g3;
Compare response of product to the product of the responses
figure
subplot(211),plot(wd,db(abs([hd.*h2 h3]))),grid
subplot(212);plot(wd,180/pi*angle([hd.*h2 h3])),grid
It appears that sos3,g3 captures the combined response of the the cascade of the original Hd and sos2.
However, a standard sos filter has the poles and zeros paired in a particular way and the sections in a particular order. It's likely that sos3 does not meet these rules. If this is important, one option would be to convert sos3 to another form and then convert back to sos
[z3,p3,k3] = sos2zp(sos3,g3);
[sos4,g4] = zp2sos(z3,p3,k3);
[g3 g4]
ans = 1×2
1.0e-05 * 0.8761 0.8761
[sos3 sos4]
ans = 9×12
1.0000 0 -1.0000 1.0000 0.5773 0.9107 1.0000 0 -1.0000 1.0000 -1.1868 0.3521 1.0000 0 -1.0000 1.0000 0.0144 0.9066 1.0000 -2.0000 1.0000 1.0000 -1.6930 0.7251 1.0000 0 -1.0000 1.0000 0.4432 0.7776 1.0000 2.0000 1.0000 1.0000 0.2735 0.7265 1.0000 0 -1.0000 1.0000 0.1146 0.7716 1.0000 -2.0000 1.0000 1.0000 -1.6178 0.7310 1.0000 0 -1.0000 1.0000 0.2735 0.7265 1.0000 2.0000 1.0000 1.0000 0.1146 0.7716 1.0000 -3.3703 2.8398 1.0000 -1.1868 0.3521 1.0000 -3.3703 2.8398 1.0000 0.4432 0.7776 1.0000 -2.3348 1.3791 1.0000 -1.6930 0.7251 1.0000 -2.3348 1.3791 1.0000 -1.5449 0.7850 1.0000 -2.2132 1.3681 1.0000 -1.6178 0.7310 1.0000 -2.2132 1.3681 1.0000 0.0144 0.9066 1.0000 -1.9680 1.2739 1.0000 -1.5449 0.7850 1.0000 -1.9680 1.2739 1.0000 0.5773 0.9107
The pole/zero pairing came out different as did the section ordering. But sos4 is, mathematically, the same filter as sos3.
h4 = freqz(sos4,wd); h4 = h4*g4;
figure
subplot(211),plot(wd,db(abs([h3 h4]))),grid
subplot(212);plot(wd,180/pi*angle([h3 h4])),grid
Forward filtering a signal through Hd, and then filtering the output of Hd through sos2 might be tricky. You'd have to figure out how to get the final states out of the Hd object, and the figure out how to transform those states as initial conditions in the filtering with sos2. Keep in mind that sosfilt, as might be used for the sos2 filtering, doesn't even accept initial conditions as an input argument.
  1 个评论
Jay
Jay 2024-1-24
编辑:Jay 2024-1-24
Thanks Paul for the detail explaination.
The pole-zero pairs are important to me and your first part of your codes, e.g., constructing sos3 and g3, works well for my application.
Thank you again for your time and efforts!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Single-Rate Filters 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by