Unrecognized function or variable 'del'.

2 次查看（过去 30 天）
Kaustubh Joshi
Kaustubh Joshi 2024-6-10
编辑： Aquatris 2024-6-10
n=0;
>> for del=0.0:0.4:pi
n=n+1;
pe(n)=1.2*sin(del);

请先登录，再回答此问题。

回答（3 个）

ScottB
ScottB 2024-6-10
del is a native function:
Delete a ROS parameter - MATLAB del (mathworks.com)
Try renaming your variable. You also need and "end" statement at the end of your loop.
Aquatris
Aquatris 2024-6-10
编辑：Aquatris 2024-6-10
Ran in:
Not recommended but you can generally overwrite native variable/function names. I cannot reproduce your problem
n = 0;
for del=0.0:0.4:pi
n=n+1;
pe(n)=1.2*sin(del);
del % disp
end
del = 0
del = 0.4000
del = 0.8000
del = 1.2000
del = 1.6000
del = 2
del = 2.4000
del = 2.8000
Star Strider
Star Strider 2024-6-10
Ran in:
That should actually work —
tic
n = 0;
for del=0.0:0.4:pi
n=n+1;
pe(n)=1.2*sin(del);
end
toc
Elapsed time is 0.026322 seconds.
pe
pe = 1x8
0 0.4673 0.8608 1.1184 1.1995 1.0912 0.8106 0.4020
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
A mnore efficient implementation would be —
tic
del=0.0:0.4:pi;
for n = 1:numel(del)
pe(n) = 1.2*sin(del(n));
end
toc
Elapsed time is 0.002461 seconds.
pe
pe = 1x8
0 0.4673 0.8608 1.1184 1.1995 1.0912 0.8106 0.4020
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
However you can take advantage of MATLAB vectorisation capabilities and just use —
tic
del=0.0:0.4:pi;
pe = 1.2*sin(del);
toc
Elapsed time is 0.001995 seconds.
pe
pe = 1x8
0 0.4673 0.8608 1.1184 1.1995 1.0912 0.8106 0.4020
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
The vectorisation approach is morst efficient in this instance (and likely others as well).
See the documentation section on Vectorization for details.
.

类别

在 Help Center 和 File Exchange 中查找有关 Startup and Shutdown 的更多信息

标签

产品


版本

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by