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Unrecognized function or variable 'del'.

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Kaustubh Joshi
Kaustubh Joshi 2024-6-10
编辑： Aquatris 2024-6-10
n=0;
>> for del=0.0:0.4:pi
n=n+1;
pe(n)=1.2*sin(del);

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回答（3 个）

ScottB
ScottB 2024-6-10
del is a native function:
Delete a ROS parameter - MATLAB del (mathworks.com)
Try renaming your variable. You also need and "end" statement at the end of your loop.
Aquatris
Aquatris 2024-6-10
编辑：Aquatris 2024-6-10
Ran in:
Not recommended but you can generally overwrite native variable/function names. I cannot reproduce your problem
n = 0;
for del=0.0:0.4:pi
n=n+1;
pe(n)=1.2*sin(del);
del % disp
end
del = 0
del = 0.4000
del = 0.8000
del = 1.2000
del = 1.6000
del = 2
del = 2.4000
del = 2.8000
Star Strider
Star Strider 2024-6-10
Ran in:
That should actually work —
tic
n = 0;
for del=0.0:0.4:pi
n=n+1;
pe(n)=1.2*sin(del);
end
toc
Elapsed time is 0.026322 seconds.
pe
pe = 1x8
0 0.4673 0.8608 1.1184 1.1995 1.0912 0.8106 0.4020
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
A mnore efficient implementation would be —
tic
del=0.0:0.4:pi;
for n = 1:numel(del)
pe(n) = 1.2*sin(del(n));
end
toc
Elapsed time is 0.002461 seconds.
pe
pe = 1x8
0 0.4673 0.8608 1.1184 1.1995 1.0912 0.8106 0.4020
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
However you can take advantage of MATLAB vectorisation capabilities and just use —
tic
del=0.0:0.4:pi;
pe = 1.2*sin(del);
toc
Elapsed time is 0.001995 seconds.
pe
pe = 1x8
0 0.4673 0.8608 1.1184 1.1995 1.0912 0.8106 0.4020
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
The vectorisation approach is morst efficient in this instance (and likely others as well).
See the documentation section on Vectorization for details.
.

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