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Please Help! Can anyone explain how to do this?

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Tony 2015-4-29

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关闭： MATLAB Answer Bot 2021-8-20

C Each number on a phone corresponds to three alphabetic characters. Write a code that prints all possible words formed (regardless of whether or not they make sense) from any 7-digit telephone number.

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the cyclist 2015-4-29

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Start by reading this, which gives a lot of help on how to solve the problem you have. Then come back here.

Tony 2015-4-29

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编辑：the cyclist 2015-4-29

在 MATLAB Online 中打开

n=input('Input a 7 digit number')
AB={ 'a b c d e f g h i j k l m n o p q r s t u v w x y z'};
for i=1:n;
  f= (i)*char(AB)/3;
end
disp(f)

this is what i have so far, I am not sure how to make 3 letter words appear for a 7 any digit phone number.

Star Strider 2015-4-29

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On my phone, ‘7’ has ‘PQRS’ while all the others (from 1-9) have 3 letters each. I would create a cell array of the letter groups, each referenced by a single digit from 1-9, create the 7-digit phone numbers, and go from there.

It would be helpful if ‘word’ was defined a bit more precisely by the maximum number of letters, especially if they don’t all have to make sense. Otherwise you could get everything from ‘a’ to ‘supercalifragilisticexpialidocious’

Guillaume 2015-4-29

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编辑：Guillaume 2015-4-29

@star, it does say from a 7-digit telephone number

Ilham Hardy 2015-4-29

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I am amazed that the word actually have a meaning, or should i say i am supercalifragilisticexpialidocious

Tony 2015-4-29

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i am totally clueless

Star Strider 2015-4-29

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@Tony — That makes two of us!

@Guillaume — Therein lies the problem.

If I’m reading the problem correctly, a 7-digit telephone number would have a total of 21 (or 22) letters, not necessarily unique since numbers can repeat.

So to me there are two possibilities:

do we map from 7 letters that can encode a 7-digit telephone number, or
from a 7-digit telephone number that can produce 21 or 22 letters?

It’s not clear to me from the question.

the cyclist 2015-4-29

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To me, it is fairly clear. You enter a 7-digit phone number, which would lead to (3^7) possible 7-letter "words" if there were exactly 3 characters per key.