Breaking a binary value into single bits

2015 5 10
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更新时间：2015 5 11
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I am wanting to break up a binary value into a row of single bits to work with (i.e. 1110101101 into ten different, single column values 1, 1, 1, 0, 1, 0, 1, 1, 0, 1). I am trying to take a text file's binary value and disperse it into an array of binary values by replacing the least significant bit of the array values with the values from the broken up binary value.

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Image Analyst
Image Analyst 2015-5-10

2 个投票

The binary value is already a string, right? If not, do this:
sBinary = dec2bin(941) % returns sBinary = '1110101101' string.
Then do this to get an integer array with just the 0 or 1 bit in its own element:
individualBits = sBinary - '0'

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Tyler Burk
Tyler Burk 2015-5-10
Thank you! Could you also help me with the next problem I have then? I have an array of binary values [1010,0010,0110,1101,1011,1110,1111,1101,1101,1000] and I want to replace the least significant bits of each of those values with the individualBits array [1,1,1,0,1,0,1,1,0,1] respectively.
It should yield [1011,0011,0111,1100,1011,1110,1111,1101,1100,1001]
Jan
Jan 2015-5-10
Please open a new thread for a new question.
Consider that there is no difference between the "binary values" [1010,0010] and [10100010], because both are represented by the string '10100010'. So please post exactly what kind of input you have: which class and size?
BinValue = ['1010','0010','0110','1101','1011']
BinValue(4:4:end) = '1'
Walter Roberson
Walter Roberson 2015-5-11
V = [1 0 1 0;0 0 1 0;0 1 1 0;1 1 0 1;1 0 1 1;1 1 1 0;1 1 1 1;1 1 0 1;1 1 0 1;1 0 0 0];
v(:,end) = [1,1,1,0,1,0,1,1,0,1];

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