Using reshape function i get wrong ans....
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b=[0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1];
>> SS=reshape(b,length(b)/8,8);
>> SS
SS =
0 0 0 0 0 0 0 0
1 0 1 0 1 0 1 0
0 0 0 0 0 0 0 0
0 1 0 1 0 1 0 1
bt i want to get
SS =
0 1 0 0 0 0 1 0
0 1 0 0 0 0 1 0
0 1 0 0 0 0 1 0
0 1 0 0 0 0 1 0
ie what my array b data.. thats i want to be in SS.. how i write code? Help me
1 个评论
Jan
2015-5-18
Where does the trailing zero column come from? It is not clear why the last and teh 2nd last column seem to have swapped.
采纳的回答
Andrei Bobrov
2015-5-18
b=[0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1];
SS=reshape(b,8,[]);
SS([end,end-1],:) = SS([end-1,end],:);
SS = SS';
6 个评论
I strongly suspect that the Arjun has got his example slightly wrong and that this step:
SS([end,end-1],:) = SS([end-1,end],:);
is unwanted. I.e, the correct answer is most likely:
SS = reshape(b, 8, [])'
@Arjun, reshape rearranges the elements by column (since matlab is column major). So, the answer is to rearrange the elements in columns of 8 rows and then transpose.
ARJUN K P
2015-5-18
ans Wrong....
ARJUN K P
2015-5-18
Jan
2015-5-18
As your screen shot shows, you get exactly the answer you've asked for. If this is not the answer you want, please give us a chance to help you and post exactly, what you want.
ARJUN K P
2015-5-18
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