Using reshape function i get wrong ans....

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b=[0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1];
>> SS=reshape(b,length(b)/8,8);
>> SS
SS =
0 0 0 0 0 0 0 0
1 0 1 0 1 0 1 0
0 0 0 0 0 0 0 0
0 1 0 1 0 1 0 1
bt i want to get
SS =
0 1 0 0 0 0 1 0
0 1 0 0 0 0 1 0
0 1 0 0 0 0 1 0
0 1 0 0 0 0 1 0
ie what my array b data.. thats i want to be in SS.. how i write code? Help me
  1 个评论
Jan
Jan 2015-5-18
Where does the trailing zero column come from? It is not clear why the last and teh 2nd last column seem to have swapped.

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2015-5-18
b=[0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1];
SS=reshape(b,8,[]);
SS([end,end-1],:) = SS([end-1,end],:);
SS = SS';
  6 个评论
ARJUN K P
ARJUN K P 2015-5-18
编辑:ARJUN K P 2015-5-18
sry its my mistake..
b=[0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1]; i want to group each 8 bits in array b.. that is i want my ans like
0 1 0 0 0 0 0 1
0 1 0 0 0 0 0 1
0 1 0 0 0 0 0 1
0 1 0 0 0 0 0 1
ARJUN K P
ARJUN K P 2015-5-18
thanku all i got ans.... special thanks to Andrei Bobrov code is working

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