Matrix Multiplication (multiply every row of a matrix to different values)
10 次查看(过去 30 天)
显示 更早的评论
Dear all,
I am looking for a way to multiply every row of a matrix to different values? Let assume we have:
A=[1, 2, 3; 4, 5, 6; 7, 8, 9]
B=[a;b;c]
I am looking for a way to have:
C=[1*a, 2*a, 3*a; 4*b, 5*b, 6*b; 7*c, 8*c, 9*c]
Thanks in advance for your comments.
0 个评论
采纳的回答
更多回答(2 个)
Paulo Silva
2011-2-28
Just a little interesting thing I've done
syms a b c
A=[1, 2, 3; 4, 5, 6; 7, 8, 9]
B=[a;b;c];C=[];
for id=1:numel(B)
C=[C A(id,:)*B(id)];
end
C
The symbolic result (only works if you have the symbolic toolbox and a valid license for it) is
[ a, 2*a, 3*a, 4*b, 5*b, 6*b, 7*c, 8*c, 9*c]
The result is symbolic and you can use the subs function to replace the letters by numbers.
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Symbolic Math Toolbox 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!