I have problem with using fopen
显示 更早的评论
hello I try to create htk file using the following code
function ht_kwrite(filename, data, frate, feakind)
[ndim, nframes] = size(data);
filid=fopen(filename,'wb','ieee-be');
fwrite(filid,nframes,'int32');% number of frames
fwrite(filid, frate, 'int32'); % frame rate in 100 nano-seconds unit
fwrite(filid, 4 * ndim, 'short'); % 4 bytes per feature value
fwrite(filid, feakind, 'short'); % 9 is USER
fwrite(filid, data, 'float');
fclose(filid);
the problem is with using fopen when create file which always return filid=-1 (the file can not created )I dont know where the problem?
回答（2 个）
Konstantinos Sofos
2015-6-12
编辑：Konstantinos Sofos
2015-6-12
Hi Ahmed,
fileID = fopen(filename,permission,machinefmt,encodingIn) additionally specifies the order for reading or writing bytes or bits in the file using the machinefmt argument. The optional encodingIn argument specifies the character encoding scheme associated with the file.
what is the wb in your code?
Please try
filid=fopen(filename,'w','ieee-be');
or
filid=fopen(filename,'w','b');
Regards
Walter Roberson
2015-6-14
Using 'wb' is accepted as being equivalent to 'w' for compatibility with C programming.
The common reason for not being able to open a file for writing is that you do not have permission to write to the directory or file. You should be checking the result of the fopen()
[fid, errmsg] = fopen(filename, 'w', 'ieee-be');
if fid < 0
error(sprintf('failed to open "%s" because "%s"', filename, errmsg));
end
1 个评论
Jan
2015-6-14
Or without sprintf:
error('failed to open "%s" because "%s"', filename, errmsg);
类别
在 帮助中心 和 File Exchange 中查找有关 Low-Level File I/O 的更多信息
2015-6-12
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
