How will my program read large data in a loop?

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Prakriti Sardana
Prakriti Sardana 2015-6-16
编辑： Stephen23 2015-6-23
I have data sets for about a 1000 objects. Each data set is a matrix with 'different no. of rows for each * 2 columns' as the matrix order. Now, I have called all the data sets in my current folder using:
files = dir('*.txt');
for i=1:length(files)
eval(['load ' files(i).name ' -ascii']);
end
which stores them as matrices X1, X2, et al. I need to assign each column of each matrix to a different variable for each, in a loop because writing separately for each object is not possible given the large number of data sets.
How do I do that?
  1 个评论
Stephen23
Stephen23 2015-6-23
编辑：Stephen23 2015-6-23
Avoid using eval for such trivial code. Learn to not use eval and your code will be more robust and easier to read.... Read this to know why:
http://www.mathworks.com/matlabcentral/answers/196952-how-to-create-new-variables-in-batches-with-strcat

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Walter Roberson
Walter Roberson 2015-6-16
http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F
http://matlab.wikia.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F
I suggest something like
files = dir('*.txt');
data = cell(length(files),2);
for i=1:length(files)
thisdata = load(files(i).name, '-ascii');
data{i,1} = thisdata(:,1);
data{i,2} = thisdata(:,2);
end
  2 个评论
Prakriti Sardana
Prakriti Sardana 2015-6-23
编辑：Prakriti Sardana 2015-6-23
Hm, thank you very much for your continued help.
Jan
Jan 2015-6-23
@Prakriti Sardana: There is always a better solution than eval.

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