working of surf function

Question

RajyaLakshmi 2015-6-24

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编辑： Stephen23 2015-6-24

Plot the following surfaces using the surf function:

a) Sine surface
x = sin(u)
y = sin(v)
z = sin(u +v )
where 0 <= u <= 2*pi, and 0 <=v <= 2*pi.

I executed the following code :

u=[0:pi/4:2*pi];
v=[0:pi/4:2*pi];
x=sin(u);
y=sin(v);
z=sin(u+v);
surf(x,y,z);colorbar;xlabel('sin(u)');ylabel('sin(v)');zlabel('sin(u+v)');title('Sine Surface');

After executing the above code I got the following error

Error using surf (line 75) Z must be a matrix, not a scalar or vector

Here Z is a matrix of size [1 9]. can anyone tell me the reason:

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Jan 2015-6-24

I've edited the question to format the code. Please use the "{} Code" button for posting code. Thanks.

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Answer 1

Stephen23 2015-6-24

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编辑：Stephen23 2015-6-24

在 MATLAB Online 中打开

surf needs matrices to plot this data, so you need to convert the two vectors u and v into matrices... this is exactly what meshgrid is for:

u = 0:pi/4:2*pi;
v = 0:pi/4:2*pi;
[uM,vM] = meshgrid(u,v);

I am sure that you can manage the rest, you just need to use the uM and vM values instead of u and v. You might also like to decrease the step size: around one twentieth looks nice.

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Answer 2

Jan 2015-6-24

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在 MATLAB Online 中打开

Please read the documentation of the surf command. There you find working examples, which explain, that Z must be a matrix of the size length(X)*length(Y):

If X and Y are vectors, length(X) = n and length(Y) = m, where [m,n] = size(Z)