Vectorizing Array -- Wrong Dimensions?
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Hi all, I'm a native C programmer and am having a hard time understanding Matlab's behavior.
I have three arrays:
sample.currtargdist (2252 x 1)
sample.targloc (1 x 2552)
distance (6 x 2252)
I can't figure out why this code results in a 2252 x 2252 matrix:
for s = 1:setsize;
distance(s,:) = sqrt((sample.RIGHT_GAZE_X-loc(s).x).^2+(sample.RIGHT_GAZE_Y-loc(s).y).^2);
end
sample.currtargdist = distance(sample.targLoc,:);
When I try something like a '1' instead of ':', I just get the first column of the matrix. I want just the first row of the output matrix.
6 个评论
Azzi Abdelmalek
2015-7-8
编辑：Azzi Abdelmalek
2015-7-8
This is not clear, what is sample.RIGHT_GAZE_X-loc? what is the value of setsize?
Nick G
2015-7-8
Jan
2015-7-8
Which one is "the output matrix"?
Nick G
2015-7-8
Nick G
2015-7-8
采纳的回答
Jan
2015-7-8
I want just the first row of the output matrix.
Perhaps you mean this:
sample.currtargdist = distance(sample.targLoc(1), :);
If targLoc has the size 1 x 2552 and distance is 6x2552, then distance(targloc,:) is expected to be 2552x2552 - or a bug, if the elements of targloc exceed the values 1:6.
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Azzi Abdelmalek
2015-7-8
0 个投票
Probably, the value of setsize is 2252, or maybe in your code, you have pre-allocated the variable distance with zeros(2252,2252)
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