log and Exponential Equations: logb^300=30, find b)

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amran Hossain
amran Hossain 2015-7-31
回答： Star Strider 2015-7-31
Exponential Equations: logb^300=30, find b)

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回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2015-7-31
syms b
sol=solve(log(b^300)==30)
Star Strider
Star Strider 2015-7-31
This is fairly straightforward.
log(b^300) = 300*log(b)
log(b) = 30/300
exp(log(b)) = b = exp(0.1)
Use MATLAB to get the numbers:
b = exp(30/300);
check = 300*log(b)
b =
1.1052
check =
30.0000e+000

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