fprintf function applied to 3D matrices

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Gabriele Granello
评论： Walter Roberson 2015-8-6
Hi guys, I'm struggling a bit with fprintf function. I have a 3D matrix A(m,n,k); m,n are properties and k is a time step. I would like to print the matrix in the format A(m,n,1) A(m,n,2) A(m,n,3) and so on till k. I though to create a big 2D matrix and then print it but I was wondering if there is a more elegant solution.
Thank you very much for your help, Gabriele
  2 个评论
Walter Roberson
Walter Roberson 2015-8-5
Are the first two lines to be
A(1,1,1) A(1,1,2) A(1,1,3) ... A(1,1,k)
A(2,1,1) A(2,1,2) A(2,1,3) ... A(2,1,k)
?
Gabriele Granello
Gabriele Granello 2015-8-6
编辑：Gabriele Granello 2015-8-6
The lines are
A(1,1,1) A(1,2,1)------A(1,n,1) A(1,1,2) A(1,2,2)---------A(1,n,2)
A(2,1,1) A(2,2,1)------A(2,n,1) A(2,1,2) A(2,2,2)---------A(2,n,2) ecc

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Walter Roberson
Walter Roberson 2015-8-5
permute() the array so that the dimension to be printed across is down the columns. Create a format by
numcol = 17; %as appropriate
colfmt = '%13.5f'; (or appropriate format)
fmt = [repmat([colfmt ' '], 1, numcol), colfmt, '\n'];
Then
fprintf(fid, fmt, PermutedArray)
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Gabriele Granello
Gabriele Granello 2015-8-6
I have used the less elegant solution for the moment. But now i will try playing with the permutation because seems an interesting function and jumping between 2D or 3D quite easy would be beneficial for my code. Thanks for your help
Walter Roberson
Walter Roberson 2015-8-6
numcol = size(A,2) * size(A,3);
fmt = [repmat([colfmt ' '], 1, numcol-1), colfmt, '\n'];
Note: if you don't mind an extra space at the end of the line, then
fmt = [repmat([colfmt ' '], 1, numcol), '\n'];

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