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reshape+loop error

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Mandy Guo
Mandy Guo 2015-8-14
评论： Walter Roberson 2015-8-14
hi, i am trying to create a loop but I got this error message: Error using reshape Size arguments must be integer scalars. Can I ask how to solve it? thanks.
for i=1:120
d{i,3}=reshape(d{i,1},m(i,4),m(i,2));
end

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回答（1 个）

Walter Roberson
Walter Roberson 2015-8-14
d{i,3}=reshape(d{i,1},m(:,4),m(:,2)); tries to use the content of all of column 4 of m as the first dimension, and the content of all of column 2 of m as the second dimension. If m has more than one column then m(:,4) and m(:,2) would come out as vectors, and it is not allowed to reshape() to a vector of sizes. If you are certain that m has only 1 column then why not explicitly code m(1,4) and m(1,2) ?
Are you sure that m has sizes in it, and not data?
  2 个评论
Mandy Guo
Mandy Guo 2015-8-14
编辑：Mandy Guo 2015-8-14
hi, b actually contains 120 cells. I need to reshape them one by one and therefore it is 120 times. However, the question here is different cells have different lengths. thats why I created a loop for this.m (i,2) and m(i,4) represent the num of columns and rows of new matrix. Can you help me develop this code? many thanks
Walter Roberson
Walter Roberson 2015-8-14
Your revised code looks appropriate, provided that the m values are integer values and that m(i,4)*m(i,2) = numel(d{i,1})

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