error: Function definitions are not permitted in this context

Question

Amine Ben Ayara 2015-8-18

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/234452-error-function-definitions-are-not-permitted-in-this-context

评论： Amine Ben Ayara 2015-8-18

Hello, I have been trying to run a code that uses for loops, and I keep getting the error message: Function definitions are not permitted in this context, at the end. Here is my original code:

function  [MN]  = ProbabiltyMatrices(X,Lam,Y)
%UNTITLED Summary of this function goes here
%   Detailed explanation goes here
 for i=1:9
for l=1:3
  for j=1:3
      Den(i,l)=exp (Y(i+1,l)* dot(X(i,:),Lam(1,:)))  + exp(Y(i+1,l)* dot(X(i,:),Lam(2,:))) +exp(Y(i+1,l)* dot(X(i,:),Lam(3,:)));    
      MN(l,j,i) = exp(Y(i+1,l)* dot(X(i,:),Lam(j,:)))/Den(i,l);   
    end    
  end
   end
  Ml =transpose(transpose(MN(:,:,1))* transpose(Y(2,:)));
   for i=2:9
   Ml(i,:)=transpose(transpose(MN(:,:,i))* transpose(Ml(i-1,:)));
   end
   M=Ml;

Can someone help please.

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Answer 1

Azzi Abdelmalek 2015-8-18

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/234452-error-function-definitions-are-not-permitted-in-this-context#answer_189674

在 MATLAB Online 中打开

ProbabiltyMatrices is a function, you can't run it by clicking run. To use this function, assign values to

X=
Lam=
Y=

Then call your function

MN = ProbabiltyMatrices(X,Lam,Y)

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Amine Ben Ayara 2015-8-18

Hey Azzi, Thank you so much for replying so quick. In fact, I have three variables which are already created and contain data that I used for this code. X, Lam & Y are the three matrices that I used.

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