IMAGE Processing(matrix comparision)

2011 12 16
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更新时间：2021 8 20
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Hi All,
if i have two matrix to be compared, and i dont want perticular element to be compaered, how do i do that in matlab..??
for Ex
A=[1 8 8
7 6 *
9 9 9]
B=[3 5 6
5 6 5
9 0 9]
as u can see a '*' symbol in matrix a, so while comparing A and B i dont want to compare the element at the '*' postion in A, with the corrosponding B's element..
please help me in this regard,
Thank You in advance.
[EDITED: Code formatted, Jan Simon]

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Chandra Kurniawan
Chandra Kurniawan 2011-12-16
Actually, you cannot put '*' in numeric array.
You can use other array to define the position of '*'
Eq :
pos = [2 3];
Muthuraj V
Muthuraj V 2011-12-22
i think u dint get my question,,,,
i have put a '*' to indicate that it can be any value....
when checking for equality between two Matrix, i don't want to check the equality of a particular element in the matrix,
say for example i dont want to compare the element in the index or position(0,2) with other matrix, so how do i do this..??

回答（1 个）

Jan
Jan 2011-12-16

0 个投票

What exactly does "compare" mean? It would be easier to create an answer, if this detail need not to be guessed.
Perhaps:
mask = logical([1, 1, 1; 1, 1, 0; 1, 1, 1]);
isequal(A(mask), B(mask))

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Muthuraj V
Muthuraj V 2011-12-22
i think u dint get my question,,,, when checking for equality between two arrays i don't want to check the equality of a particular element in the matrix, say for example i dont want to compare the element in the index or position(0,2) withe other matrix, so how do i do this..??
Image Analyst
Image Analyst 2011-12-24
I thought Jan's answer sounds exactly like what you want. It compares all elements for equality except the (0,2) elements which it ignores. Isn't that exactly what you want?
Muthuraj V
Muthuraj V 2011-12-27
yes thats what i want, but i dint get exactly how this code works, can u please explain me..
mask = logical([1, 1, 1;
1, 1, 0;
1, 1, 1]);
isequal(A(mask), B(mask))
Walter Roberson
Walter Roberson 2011-12-27
http://www.mathworks.com/help/techdoc/math/f1-85462.html#bq7egb6-1
Muthuraj V
Muthuraj V 2011-12-30
Thanks a Lot...

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Muthuraj V
2011-12-16

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